1sqmeter=100x100=100000sqcm
in 1sqcm there are 23/100=.23 grass plants
Therefore, there will be .23x100000=2300 grass plants in a sq.meter
Answer:
I will provide the steps below.
Step-by-step explanation:
First, You will need to plug in the 8.
2(8)-(1/-3)=-5
Multiply
16-(-1/3)=-5
If we have two negitive it turns into possitive.
16+1/3=-5
16+1/3=-5
This statement is not true becuase if y=8 the equation will be (16+1/3)=5
*Make sure your giving me the right eqution otherwise this statment is false.*
Answer: n=-6
Step-by-step explanation:
First you have to isolate the variable
4+1/6n=3
So you have to subtract 4 from both sides to get
1/6n=-1
Now all you have to do is divide both sides by 1/6
-1 divided by 1/6 =-6
So n=-6
Answer: The height of one propeller tip is 3.68 feet when t= 3.5 minutes.
Step-by-step explanation:
Given: The height of one propeller tip as a function of time is given by
), where h is the height in feet and t is the time in minutes.
Put t = 3.5 , we get

Hence, The height of one propeller tip is 3.68 feet when t= 3.5 minutes.
Cost of 1 apple is $ 1.5 and cost of 1 pear is $ 1.25
<h3><u>Solution:</u></h3>
Let "a" be the cost of 1 apple
Let "p" be the cost of 1 pear
Given that,
<em><u>One week Beth bought 3 apples and 8 pears for 14.50</u></em>
So we can frame a equation as:
3 apples x cost of 1 apple + 8 pears x cost of 1 pear = 14.50

3a + 8p = 14.50 ----- eqn 1
<em><u>The next week she bought 6 apples and 4 pears and paid 14$</u></em>
So we can frame a equation as:
6 apples x cost of 1 apple + 4 pears x cost of 1 pear = 14

6a + 4p = 14 ---- eqn 2
<em><u>Let us solve eqn 1 and eqn 2 to find values of "a" and "p"</u></em>
Multiply eqn 2 by 2
12a + 8p = 28 ---- eqn 3
Subtract eqn 1 from eqn 3
12a + 8p = 28
3a + 8p = 14.50
(-)----------------
9a = 13.5
<h3>a = 1.5</h3>
From eqn 1,
3a + 8p = 14.50
3(1.5) + 8p = 14.50
4.5 + 8p = 14.50
8p = 10
<h3>p = 1.25</h3>
<em><u>Thus we have:</u></em>
Cost of 1 apple is $ 1.5 and cost of 1 pear is $ 1.25