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3 years ago

A manufacturer introduces a new computer, and the marketing department uses the function s(t)=250/3+4e^-0.54t to

Mathematics

2 answers:

kirill [66]3 years ago

7 0

Answer: it’s C

Step-by-step explanation:

Natali [406]3 years ago

4 0

Answer:

Step-by-step explanation:

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The line plot shows the number of points scored by Josh in his basketball games. How many games did Josh score more than six poi

andre [41]

Answer:

3 games.

Step-by-step explanation:

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3 years ago

Solve for x under the assumption that x > 0. Enter your answer in interval notation using grouping symbols.

Delicious77 [7]

Starting with x−24/x<10 multiply everything by x. x^2-24<10x Subtract 10x from both sides. x^2-10x-24 < 0 Factor. (x-12)(x+2) < 0 (x+2) is always positive since x > 0, but (x-12) is negative when x is a value between 0 and 12. This negative value for (x-12) satisfies that the left side is less than 0. Thus the solution set for x is (0,12).

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3 years ago

Round 145 to the nearest hundreds place. 100 140 150 200

wariber [46]

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Step-by-step explanation:

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3 years ago

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Solve either of the correct equations using any method. Round to the nearest whole number d= Days

galina1969 [7]

Where is the question m8?

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3 years ago

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Among a group of 100 people, 68 can speak English, 45 can speak French, 42 can speak Spanish. 27 can speak both English and Fren

Nat2105 [25]

Answer:

Step-by-step explanation:

Given

No of People who can speak English is $n(E)=68$

No of People who can speak French is $n(F)=45$

No of People who can speak Spanish is $n(S)=42$

No of People who can speak both English and French $n\left ( E\cap F\right )=27$

No of People who can speak both English and Spanish $n\left ( E\cap S\right )=25$

No of People who can speak both French and Spanish $n\left ( F\cap S\right )=16$

No of people who can speak all languages is $n\left ( E\cap F\cap S\right )=9$

no of People who can Speak at least one Language is

$n\left ( E\cup F\cup S\right )=n\left ( E\right )+n\left ( F\right )+n\left ( S\right )-n\left ( E\cap F\right )-n\left ( E\cap S\right )-n\left ( F\cap S\right )+n\left ( E\cap F\cap S\right )$

$n\left ( E\cup F\cup S\right )=68+45+42-27-25-16+9=96$

Probability that Randomly selected can speak at least 1 of these languages

$P=\frac{96}{100}=0.96$

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3 years ago