Answer:
Step-by-step explanation:
The problem states that there are only two types of busses - M104 and M6 with probable occurence of 0.6 and 0.4 respectively.
If the average number of busses arriving per hour is λ, the average number of M6 busses per hour is 0.4λ
Now consider a set of 3 M6 busses as an event. The average number of such events per hour will be
μ = 0.4λ / 3
The expected number of hours for the event "THIRD M6 arrives", let's say X is
E[X] = 1 / μ ( exponential distribution) = 3 / 0.4λ
= 7.5 / λ
The variance of event X is =
![Var[x] = \frac{1}{U^2} = \frac{56.25}{\lambda ^2}](https://tex.z-dn.net/?f=Var%5Bx%5D%20%3D%20%5Cfrac%7B1%7D%7BU%5E2%7D%20%3D%20%5Cfrac%7B56.25%7D%7B%5Clambda%20%5E2%7D)
I need to know how many storys there are in order to help you
sorry its a little messy!! not good at drawing with a finger haha. all you need to do is follow pedmas and isolate, knowing that a right angle=90°. hope this helps!<3<3
Answer:
88
Step-by-step explanation:
this question is a question that involves the use of the statistical principles of finding average
let the summation of the six scores of the biology test be represented as ∑x
∴ ∑x÷ 6=74
∑x=74 × 6
=444
444 is the summation of all the scores of all the six biology scores reuben had
the next test would be his 7th
let y represent the score for the 7th test
therefore, 
= 76
444 + y = (76 × 7)
444 + y = 532
y=88
Reuben needs to score 88 to raise his average to 76
