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3 years ago

(look at image) can i get help with these two?

Mathematics

1 answer:

serg [7]3 years ago

6 0

Answer:

1. x = 2, AC = 30, AB - 4

2. y = 4, AB = 34, BC = 34

Step-by-step explanation:

1. AB + BC = AC so 26 + (10 - 3x) = 14x +2 and then add 3x to both sides and subtract 2 from both sides to get x on one side and an integer on the other side which is 34 = 17x and then divide 17 from both sides to get x = 2 and then substitute x into the AC and AB equations to find the values its equal to.

2. The symbol in the given means that the two lengths are congruent which means they are equal to each other so you put the two equations equal to each other and solve for y. 9y -2 = 14 + 5y, so subtract 5y from both sides and add two to both sides to get 4y = 16 and then divide both sides by 4 to get y = 4 and then substitute in the answer to find the lengths of AB and BC.

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Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

2x + 7= -11 please help

Dvinal [7]

Answer:

x = -9

Step-by-step explanation:

You are solving for x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

First, subtract 7 from both sides:

2x + 7 (-7) = -11 (-7)

2x = -11 - 7

2x = -18

Next, divide 2 from both sides:

(2x)/2 = (-18)/2

x = -18/2

x = -9

x = -9 is your answer.

6 0

3 years ago

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What is an equation in point-slope form of the line that passes through the point (6, −2) and has a slope of 3? A. y + 2 = 3(x −

Nostrana [21]

Answer:

answer A is correct because the formula of equation in point slope is

y-y1=m(x-x1)

where,(x1,y1)point is given that is (6,-2)

slope=m=3

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3 years ago

5.6372 divided by 0.17

polet [3.4K]

33.16. (Hint: You can use a calculator or search it up on the web)

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Hitman42 [59]

I think it is 1 I am sorry if I am wrong

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3 years ago