Answer:
Step-by-step explanation:
The main idea is that I would like to pay less than what I'm expecting to win, so in that way, I get a profit out of playing this game. Let X be the number of tosses until I get a Heads. By definition, this is a geometric random variable with parameter p = 1/2.
Let Y the amount I received for playing. So, we want to calculate the expected value of Y.
We can calculate it as follows
![E[Y] = 2 P(X=1)+ 4 P(X=2)+ 8 P(X =3) + \dots = \sum_{n=1}^infty 2^n P(X=n)](https://tex.z-dn.net/?f=E%5BY%5D%20%3D%202%20P%28X%3D1%29%2B%204%20P%28X%3D2%29%2B%208%20P%28X%20%3D3%29%20%20%2B%20%5Cdots%20%20%3D%20%5Csum_%7Bn%3D1%7D%5Einfty%202%5En%20P%28X%3Dn%29)
Since X is a geometric random variable, we have that 
Then,
So, we expect to have an infinite amount. Given this, we can pay as much as we want to play the game.
The answer to the first one is D)11 and the answer to the second is A)14
Answer:
S = 1
Step-by-step explanation:
If you add a positive 1 to -20, you would get -19
Answer:
U need to post a pic so I can see ur question
Step-by-step explanation: