What are the dimensions of the lightest open-top right circular cylindrical can that will hold a volume of 2744 cmcubed3?
1 answer:
Answer:
r=2.808cm h = 100cm
then we get volume of cylinder that is 2744 As explained below
Step-by-step explanation:
Volume of cylinder = πr²h
Surface area of cylinder = 2πrh +πr² (1)
h= 2744 /πr²
put value oh h in equation (1)
Area =[2πr] 2744 /πr²
=[5488/r +πr²]
dA/dx=0
i.e 2πr=5488/r²
Solving this r.r= ∛5488/2π
=2.808
taking second derivation we get 100
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