The answer to the question
solution:
Consider the differential equation,
7ty + (1+t2)1/2y1 = 0
Rewrite the DE as,
(1+t2)1/2dy = - 7ty
dy/y = -7t/√1+t2 dt
in y = -7(1+t2) + c
y = ce-7(1+t2)
given,
y(0) = 1 => ce-7 = -1 => c = e7
ᴪ (t,y) = y -ce ᴪ(0,1)(1+t2)
Answer:
It will stay the same
Step-by-step explanation:
You can't add unlike terms
Answer:
73.72
Step-by-step explanation:
Using law of Sines in area:
A(triangle) = S1 * S2 * sin(theta) /2
A(triangle) = 12 * 15 * sin(55) / 2 = about 73.72 when rounded
ANSWER: 73.72
