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3 years ago

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Yesterday, Katrina was just $23.75 below her fundraising goal. She got a check today for $12.33 to put toward the fundraiser. De

scribe Katrina’s progress toward the goal.

1 answer:

Degger [83]3 years ago

5 0

Answer:

She is $11.42 away from her goal

Hope that helps!

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Wo samples are ________________ if the sample values are paired.

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Triangle jkl is right of triangle what is the length of JK

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3 years ago

Okie is a low western lowland gorilla living at the frankline park zoo near boston, ma. he loves to fingerpaint. many of his pai

Virty [35]

13500-1500= 12000/5=2400

12000-2400= 9600

$9600 most expensive painting

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3 years ago

Could someone help? picture Is included. "Even More Situations, Diagrams, and Equations"

sammy [17]

Answer:

story 1- B and story 2-A
x and y is the amount of flyers she gave to each volunteer.
3x+12=90 3y+36=90
x= 26 y=18

3x+12=90

3x+12-12=90-12

3x=78

3x/3=78/3

x=26

3y+36=90

3y+36-36=90-36

3y=54

3y/3=54/3

y=18

I hope this is good enough:

7 0

3 years ago

Let ρ = x3 + xe−x for x ∈ (0, 1), compute the center of mass.

hram777 [196]

The center of mass is mathematically given as

$\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

<h3>What is the center of mass.?</h3>

Determine the center of mass in one dimension:

Represent the masses at the respective distances.

$\begin{|c|c|} Masses \ & \ \ \ \ \ \ \ \ \ \ \ \ \ \ Located at \\\rho=x^{3}+x \cdot e^{-x} & \ \ \ \ x \in(0,1)$ \\\end$

We calculate the total mass of the system.

$\begin{aligned}m &=\int_{0}^{1} \rho \cdot d x \\& m =\int_{0}^{1}\left(x^{3}+x \cdot e^{-x}\right) \cdot d x \\&m =\left|\frac{x^{4}}{4}-(x+1) e^{-x}\right|_{0}^{1} \\&m =\left(\frac{5}{4}-\frac{2}{e}\right)\end{aligned}$

Step 03: Calculate the moment of the system.

$\begin{aligned}M &=\int_{0}^{1}(\rho \cdot x) \cdot d x \\& M=\int_{0}^{1}\left(x^{4}+x^{2} \cdot e^{-x}\right) \cdot d x \\&M =\left|\frac{x^{5}}{5}-\left(x^{2}-2 x+2\right) \cdot e^{-x}\right|_{0}^{1} \\&M=\left(\frac{11}{5}-\frac{5}{e}\right)\end{aligned}$

we calculate the center of mass.

$\begin{aligned}\bar{x} &=\left(\frac{M}{m}\right) \\& \bar{x}=\left\{\left(\frac{\left.11-\frac{5}{5}\right)}{\left(\frac{5}{4}-\frac{2}{e}\right)}\right\}\right.\\& \bar{x}=\left(\frac{11 e-25}{5 e}\right) \cdot\left(\frac{4 e}{5 e-8}\right) \\&\bar{x}=\left(\frac{44 e-100}{25 e-40}\right)\end{aligned}$

Read more about the center of mass.

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8 0

2 years ago

Problem: One-half of Alvin's age two years from now plus one-third of his age three years ago

Nadya [2.5K]

Answer:

24.

Step-by-step explanation:

Let's make the answer a variable, alright?

20 = (x - 3)/3 + 3(x + 2)

Get rid of the fractions.

120 = 2(x-3) + 3(x + 2)

120 = 2x - 6 + 3x + 6

120 = 5x

x = 24.

24 is your answer.

6 0

3 years ago