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den301095 [7]
3 years ago
9

Two numbers are in the ratio 17:13. If their H.C.F. is 15. What are the numbers ?

Mathematics
1 answer:
Molodets [167]3 years ago
8 0

Answer:

b

Step-by-step explanation:

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Round the number. Write the result as a product of a single digit and a power of 10. 0.00000124
-BARSIC- [3]

0.000001

10^-6

hope this helps :))

8 0
2 years ago
Read 2 more answers
1. A relation is plotted as a linear function on a coordinate plane starting at point C at (3, –2) and ending at point D at (–2,
vladimir2022 [97]
I think it’s C I’m not for sure
5 0
3 years ago
Help me pleaseeeeeeeeeeeeeee
dangina [55]

Answer:

W=1000C/tc

Step-by-step explanation:

First multiply both side 1000: 1000C=Wtc

Divide both side by tc: 1000C/tc=W (t, c ≠0)

7 0
3 years ago
A population of fish in a lake is 14000 in 2010. The population decreases 6% annually. What is the population in 2019
kodGreya [7K]

Answer:

8022.

Step-by-step explanation:

Let x be the number of years after 2010.

We have been given a population of fish in a lake is 14000 in 2010. The population decreases 6% annually.

We can see that population of fish is the lake is decreasing exponentially as it is decreasing 6% annually.

Since we know that an exponential function is in form: y=a*b^x, where,

a = Initial value,

b = For decrease or decay b is in form (1-r) where r represents decay rate in decimal form.

Let us convert our given decay rate in decimal form.

6\5=\frac{6}{100}=0.06

Upon substituting our given values in exponential form of function we will get the population of fish in the lake after x years as:

y=14,000*(1-0.06)^x

y=14,000*(0.94)^x

Let us find x by subtracting 2010 from 2019.

x=2019-2010=9

Upon substituting x=9 in our function we will get,

y=14,000*(0.94)^9

y=14,000*0.5729948022286167

y=8021.927\approx 8022

Therefore, the population of fish in 2019 will be 8022.

6 0
3 years ago
S<br>solve for X<br>2x - Px = 5​
maxonik [38]

Answer:

2x - P = 5 \\ x(2 - P) = 5 \\  \boxed{x =  \frac{5}{(2 - P)} }

5 0
3 years ago
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