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3 years ago

12

in a fish bowl there were 12 fish, some little, others big. if each of the big fish ate 2 little fish and then the little fish w

ere all gone, how many fish were left in the bowl?

2 answers:

hjlf3 years ago

8 0

There are 4 fish left because 2 x 4 = 8, and 8 + 4 = 12.

Charra [1.4K]3 years ago

3 0

There will be 4 big fish left.

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Solve log_8 12 = x – 2 . Round your answer to four decimal places.

Aleksandr-060686 [28]

Step-by-step answer:

Let's attack the left side:

log_8 12 = log (base 8) 12 = log(12)/log(8) = 1.1949875 (approx.)

Next solve

log_8 12 = x-2

log(12)/log(8) = x-2

x = 2 + log(12)/log(8)

= 3.195 (to one thousandth)

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4 years ago

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An athlete's speed on her bike is 14mph faster than her average speed running. She can bike 31.5 miles in the same time that it

scoundrel [369]

You would cross multiply.
14 over 31.5
and X over 10.5
10.5 times 14 is 147
divide that by 31.5 which is 4 1/3
and that is how fast she can run
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3 years ago

If f(x) = x2 - 2x and g(x) = 6x + 4 for which value of x does (t +g)(x)=0

Vinil7 [7]

Answer:

-2

Assumption:

Find the value of x such that $(f+g)(x)=0$ .

Step-by-step explanation:

$(f+g)(x)=0$

$f(x)+g(x)=0$

$(x^2-2x)+(6x+4)=0$

Combine like terms:

$x^2+4x+4=0$

This is not too bad too factor on the left hand side since 2(2)=4 and 2+2=4.

$(x+2)(x+2)=0$

$(x+2)^2=0$

So we need to solve:

$x+2=0$

Subtract 2 on both sides:

$x=-2$

Let's check:

$(f+g)(-2)$

$f(-2)+g(-2)$

$((-2)^2-2(-2))+(6(-2)+4)$

$(4+4)+(-12+4)$

$(8)+(-8)$

$0$

0 was the desired output of $(f+g)(x)$ .

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3 years ago

In △ABC, ∠ABC = 60 degrees .

ira [324]

A given<u> shape</u> that is <em>bounded</em> by three <u>sides</u> and has got three <em>internal angles</em> is referred to as a <u>triangle</u>. Thus the <em>value</em> of <u>PB</u> is 8.0 units.

A given <em>shape</em> that is <u>bounded</u> by three<em> sides</em> and has got three <em>internal angles</em> is referred to as a <u>triangl</u>e. Types of <u>triangles</u> include right angle triangle, isosceles triangle, equilateral triangle, acute angle triangle, etc. The sum of the<em> internal angles</em> of any <u>triangle</u> is $180^{o}$ .

In the given question, point<u> P</u> is <u>center</u> of the given <u>triangle</u> such that <APB = <APC = <BPC = $120^{o}$ . Such that <u>line</u> PB <em>bisects</em> <ABC into two <u>equal</u> measures of $30^{o}$ .

Thus;

<ABP = $30^{o}$

Thus,

<ABP + <APB + <BAP = $180^{o}$

30 + 120 + <BAP = $180^{o}$

<BAP = $180^{o}$ - 150

<BAP = $30^{o}$

Apply the <em>Sine rule</em> to determine the value of PB, such that;

$\frac{a}{SinA}$ = $\frac{b}{SinB}$

$\frac{8}{Sin 30}$ = $\frac{PB}{Sin 30}$

BP = $\frac{8*Sin 30}{Sin 30}$

= 8

BP = 8.0

Therefore, the value of <u>PB</u> = 8 units.

For more clarifications on Sine rule, visit: brainly.com/question/27174058

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2 years ago

Find the area of a circle with a diameter of 5 cm.

sergeinik [125]

Answer:

19.635

Step-by-step explanation:

A=pie Radius^2

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3 years ago

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