<h2>
Maximum area is 25 m²</h2>
Explanation:
Let L be the length and W be the width.
Aidan has 20 ft of fence with which to build a rectangular dog run.
Fencing = 2L + 2W = 20 ft
L + W = 10
W = 10 - L
We need to find what is the largest area that can be enclosed.
Area = Length x Width
A = LW
A = L x (10-L) = 10 L - L²
For maximum area differential is zero
So we have
dA = 0
10 - 2 L = 0
L = 5 m
W = 10 - 5 = 5 m
Area = 5 x 5 = 25 m²
Maximum area is 25 m²
The volume of the cube is (8 x 8 x 8) = 8³ = <em>512 cubic inches</em> (exact)
<span>"Simplifying
0.2y = 0.5x + 0.1
Reorder the terms:
0.2y = 0.1 + 0.5x
Solving
0.2y = 0.1 + 0.5x
Solving for variable 'y'.
Move all terms containing y to the left, all other terms to the right.
Divide each side by '0.2'.
y = 0.5 + 2.5x
Simplifying
y = 0.5 + 2.5x"</span>
Answer:
81.7
Step-by-step explanation:
90.7-18 divided by 2 = 81.7 or 82 simplified
Answer:
3/10 or three-tenths
Step-by-step explanation:
Hope this helps=D
