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Ad libitum [116K]
3 years ago
8

Using the illustration below, calculate the area of the circle.

Mathematics
1 answer:
Lynna [10]3 years ago
4 0

Answer:

Where is the illustration?

Step-by-step explanation:

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Point Y

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Is 10x+15 equivalent to 5(2x+3)
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Mary takes a sightseeing tour on a helicopter that can fly 450 miles against a 35 mph headwind. In the same amount of time it ca
monitta

Answer:

V = 160mph

Step-by-step explanation:

We need to start from the formula of speed: V=d/t

We have two travels, with and against the wind, both done in the same time.

Clearing t from the formula, we will have: t=d/V2

450miles/V-35mph (speed of the wind is subtracted)

702miles/V+35mph (speed of the wind is subtracted)

Now, we find V:

450miles/V-35mph = 702miles/V+35

450*V+35 = 702*V-35

450V+15,750 = 702V-24,570

702V-450V = 15,750 + 24,570

252V = 40,320

V = 40,320/252

V = 160mph

5 0
3 years ago
Find the function of which is the solution of 36y"-48y'-48y=0 with initial conditions y1(0)=1. y1'(0)=0
lilavasa [31]

Answer:

y=\frac{1}{4} e^{2x}+\frac{3}{4} e^{-\frac{2}{3}x }

Step-by-step explanation:

Let,  D=\frac{d}{dx}

Now, us simplify the given differential equation and write it in terms of D,

36y''-48y'-48y=0

or, 3y''-4y'-4y=0

or, (3D^2-4D-4)y=0

We have our auxiliary equation:

3D^2-4D-4=0

or, (3D+2)(D-2)=0

or, D=2, - \frac{2}{3}

Therefore our solution is,

y=Ae^{2x}+Be^{- \frac{2}{3}x}

and, y'=2Ae^{2x}-\frac{2}{3}Be^{\frac{2}{3}x }

Applying the boundary conditions, we get,

A+B=1

2A-\frac{2}{3}B=0

Solving them gives us,

A=\frac{1}{4} ,B=\frac{3}{4}

Hence,

y=\frac{1}{4} e^{2x}+\frac{3}{4} e^{-\frac{2}{3}x }

4 0
3 years ago
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