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<u>Answer:</u> 3 moles of water are formed. The limiting reagent is Oxygen atom and the excess reagent is Hydrogen atom.
<u>Explanation:</u>
From the image provided, there are 8 moles of Hydrogen atom and 3 moles of Oxygen atom.
The equation for the formation of water is given by:
By Stoichiometry,
1 mole of Oxygen atom reacts with 2 moles of Hydrogen atom.
So, 3 moles of Oxygen atom will react with = of Hydrogen atom.
The required amount of Hydrogen atom is less than the given amount of Hydrogen atom, hence, it is considered as an excess reagent.
Therefore, Oxygen atom is the limiting reagent because it limits the formation of product.
By Stoichiometry of the reaction:
1 moles of oxygen atom produces 1 mole of water molecule.
So, 3 moles of oxygen atom will produce = of water molecule.
Thus, 3 moles of water are formed. The limiting reagent is Oxygen atom and the excess reagent is Hydrogen atom.
The conclusion cannot be validated because other factors such as the amount of sunlight water location also play a vital role in germinate
Answer:
The final molarity of nitrate anion in the solution is 0.258 M.
Explanation:
Mass of barium nitrate 1.73 g
Moles of barium nitrate =
1 mole of barium nitrate gives 2 moles of nitrate ions,then 0.00662 mol of barium nitrate will give :
of nitrate ions
moles of nitrate ion added to the solution = 0.01324 mol
Molarity of the barium nitrate solution = 63.0 mM = 0.063 M
1 mM = 0.001 M
Volume of barium nitrate solution = 100 mL = 0.100 L
1 m L = 0.001 mL
Moles of barium nitrate in the solution = n
Moles of nitrate ion in solution = 2 0.0063 × mol = 0.0126 mol
Total moles og nitrate ions = 0.01324 mol + 0.0126 mol = 0.02584 mol
Final molarity of nitrate anion in the solution.:
The final molarity of nitrate anion in the solution is 0.258 M.
Answer:
Explanation:
Slow but able to move past one another