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Novosadov [1.4K]
3 years ago
10

How many atoms are in lead ii bicarbonate​

Chemistry
1 answer:
sertanlavr [38]3 years ago
4 0

Answer:

11 atoms

Explanation:

The formula for lead(II) bicarbonate is: Pb(HCO3)2.

Atoms in Pb(HCO3)2:

Pb=1, H=1×2, C=1×2, O=3×2

1+1×2+1×2+3×2

=1+2+2+6

=11 atoms

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Realiza los cálculos para determinar la cantidad de KOH 90%, que se necesita para preparar 100 ml de solución 1N.
attashe74 [19]

Answer:

6.23 KOH 90% son necesarios

Explanation:

Una solución 1N de KOH requiere 1equivalente (En KOH, 1eq = 1mol) por cada litro de solución.

Para responder esta pregunta se requiere hallar los equivalentes = Moles de KOH para preparar 100mL = 0.100L de una solución 1N. Haciendo uso de la masa molar de KOH y del porcentaje de pureza del KOH se pueden calcular los gramos requeridos para preparar la solución así:

<em>Equivalentes KOH:</em>

0.100L * (1eq / L) = 0.100eq = 0.100moles

<em>Gramos KOH -Masa molar: 56.1056g/mol-:</em>

0.100moles * (56.1056g/mol) = 5.61 KOH se requieren

<em>KOH 90%:</em>

5.61g KOH * (100g KOH 90% / 90g KOH) =

<h3>6.23 KOH 90% son necesarios</h3>
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