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3 years ago

4x+8y=17 Solve for y

Mathematics

2 answers:

Advocard [28]3 years ago

6 0

Answer:

4x + 8y= 17

8y = 17 - 4x

y = (17-4x)÷8

olasank [31]3 years ago

3 0

Answer:

4x + 8y = 17

Solve for y.

You want to get y on one side of the equal sign by itself so... you subtract 4x from both sides to get:

8y = -4x + 17

Then you divide both sides by 8 to get:

y= -4x/8 +17/8

Then simplify the fractions to get:

y = -2x/4 + 17/8

Step-by-step explanation:

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22% of adults would pay more for environmentally friendly products he randomly select 10 adults find the probability that the nu

Anettt [7]

Answer: 0.383 and 0.6671

Step-by-step explanation:

Take 22%, that is 0.22 to be probability of success.

That means "1-0.22 = 0.78" is the probability of failure.

When dealing with selection in probability mathematics, the combination equation is used.

Probability of selecting number 'r' as a successful outcome from a given number 'n' is given as

nCr * p^r * q^n-r

Where p is the probability of success= 0.22

q is the probability of failure= 0.78

n is the total number of sample =10

r is the varying outcome of number of success.

For the first question, number of success is asked to be everything more than 2, that is probability of choosing 3,4,5,6,7,8,9,10 people with a successful outcome (adults who will pay more for environmentally friendly product.)

Instead of going through the long process of checking probability of success for choosing 3,4,5,6,7,8,9,10 adults who will pay more, we can simply find the probability of choosing 0,1,2 adults who will pay more and subtract the answer from 1.

By doing this, we first check for probability of choosing 0 adult that will pay More and this is gotten by putting r=0 in our probability Formula. The Formula becomes

=10C0 * 0.22^0 * 0.78^10

=1 *1 * 0.0834= 0.0834

Hence, Probability of Choosing 0 adult that will Pay more is 0.0834

To Check for probability of choosing 1 adult that will pay more becomes

=10C1 * 0.22^1 * 0.78^9

=10 * 0.22 * 0.1069 = 0.2352

Hence, Probability of choosing 1adult that will pay more = 0.2352

To Check for the probability of choosing 2adults that will pay more becomes

=10C2 * 0.22^2 * 0.78^8

=45 * 0.0484 * 0.1370 = 0.2984

Therefore the total sum of choosing 0,1,2 adults that are willing to pay more becomes

= 0.0834+ 0.2352+ 0.2984 = 0.617

So to determine the probability of choosing more than 2 adults, that is, 3,4,5,6,7,8,9,10 adults that are willing to pay more, we subtract 0.617 from 1.

This gives 1-0.617 = 0.383

Hence, probability of choosing more than 2 people that are willing to pay more than 2 = 0.383.

To determine the probability of choosing between two and five people inclusive, we follow the same probability formular but r becomes 2,3,4,5 differently.

For probability of choosing 2 adults, we already calculated it to be 0.2984 earlier.

For probability of choosing 3 adults, it becomes

10C3 * 0.22^3 * 0.78^7

=120* 0.0106 * 0.1757 = 0.2235

For the probability of choosign 4 adults, it becomes

10C4 * 0.22^4 * 0.78^6

= 210 * 0.0023 * 0.2252 = 0.1088

For the probability of choosing 5 adults, it becomes

10C5 * 0.22^5 * 0.78^5

= 252 * 0.0005 * 0.2887 = 0.0364

Hence, the probability of choosing between 2 and 5 adults becomes

0.2984 + 0.2235 + 0.1088 + 0.0364 = 0.6671

5 0

3 years ago

Convert 5. 06km to metres

djyliett [7]

Answer:

5060

Step-by-step explanation:

3 0

3 years ago

1-What is the sum of the series? ∑j=152j Enter your answer in the box.

tangare [24]

Answer:

Please see the Step-by-step explanation for the answers

Step-by-step explanation:

∑ $\left \ {{5} \atop {j=1}} \right.$ 2j

The sum of series from j=1 to j=5 is:

∑ = 2(1) + 2(2) + 2(3) + 2(4) + 2(5)

= 2 + 4 + 6 + 8 + 10

∑ = 30

This question is not given clearly so i assume the following series that will give you an idea how to solve this:

∑ $\left \ {{4} \atop {k=1}} \right.$ 2k²

The sum of series from k=1 to j=4 is:

∑ = 2(1)² + 2(2)² + 2(3)² + 2(4)²

= 2(1) + 2(4) + 2(9) + 2(16)

= 2 + 8 + 18 + 32

∑ = 60

∑ $\left \ {{4} \atop {k=1}} \right.$ (2k)²

∑ = (2*1)² + (2*2)² + (2*3)² + (2*4)²

= (2)² + (4)² + (6)² + (8)²

= 4 + 16 + 36 + 64

∑ = 120

∑ $\left \ {{4} \atop {k=1}} \right.$ (2k)²- 4

∑ = (2*1)²-4 + (2*2)²-4 + (2*3)²-4 + (2*4)²-4

= (2)²-4 + (4)²-4 + (6)²-4 + (8)²-4

= (4-4) + (16-4) + (36-4) + (64-4)

= 0 + 12 + 32 + 60

∑ = 104

∑ $\left \ {{4} \atop {k=1}} \right.$ 2k²- 4

∑ = 2(1)²-4 + 2(2)²-4 + 2(3)²-4 + 2(4)²-4

= 2(1)-4 + 2(4)-4 + 2(9)-4 + 2(16)-4

= (2-4) + (8-4) + (18-4) + (32-4)

= -2 + 4 + 14 + 28

∑ = 44

∑ $\left \ {{6} \atop {k=3}} \right.$ (2k-10)

∑ = (2×3−10) + (2×4−10) + (2×5−10) + (2×6−10)

= (6-10) + (8-10) + (10-10) + (12-10)

= -4 + -2 + 0 + 2

∑ = -4

1+1/2+1/4+1/8+1/16+1/32+1/64

This is a geometric sequence where first term is 1 and the common ratio is 1/2 So

a = 1

This can be derived as

1/2/1 = 1/2 * 1 = 1/2

1/4/1/2 = 1/4 * 2/1 = 1/2

1/8/1/4 = 1/8 * 4/1 = 1/2

1/16/1/8 = 1/16 * 8/1 = 1/2

1/32/1/16 = 1/32 * 16/1 = 1/2

1/64/1/32 = 1/64 * 32/1 = 1/2

Hence the common ratio is r = 1/2

So n-th term is:

$ar^{n-1}$ = $1(\frac{1}{2})^{n-1}$

So the answer that represents the series in sigma notation is:

∑ $\left \ {{7} \atop {j=1}} \right.$ $(\frac{1}{2})^{j-1}$

−3+(−1)+1+3+5

This is an arithmetic sequence where the first term is -3 and the common difference is 2. So

a = 1

This can be derived as

-1 - (-3) = -1 + 3 = 2

1 - (-1) = 1 + 1 = 2

3 - 1 = 2

5 - 3 = 2

Hence the common difference d = 2

The nth term is:

a + (n - 1) d

= -3 + (n−1)2

= -3 + 2(n−1)

= -3 + 2n - 2

= 2n - 5

So the answer that represents the series in sigma notation is:

∑ $\left \ {{5} \atop {j=1}} \right.$ (2j−5)

6 0

3 years ago

Please help me !! :))))

mario62 [17]

I think a is your answer

7 0

3 years ago

Read 2 more answers

Hey I need this answered i have no clue what to put pls help

Molodets [167]

Answer:

b is correct for Maria but c is correct for the boy

4 0

3 years ago