How many hours of sleep do most people need to function properly?

Which of the following p values will lead us to reject the null hypothesis if the level of significance equals .05?

V125BC [204]

Answer:

So then our significance level is $\alpha=0.05$ and we need to remember these two conditions:

1) If the p value $p_v$ we have enough evidence to reject the null hypothesis at the significance level given

2) If the p value $p_v \geq \alpha$ we have enough evidence to FAIL reject the null hypothesis at the significance level given

And baed on the options we see that the only possibility would be:

d. 0.015

Step-by-step explanation:

We want to know for which value we would REJECT the null hypothesis.

So then our significance level is $\alpha=0.05$ and we need to remember these two conditions:

1) If the p value $p_v$ we have enough evidence to reject the null hypothesis at the significance level given

2) If the p value $p_v \geq \alpha$ we have enough evidence to FAIL reject the null hypothesis at the significance level given

And baed on the options we see that the only possibility would be:

d. 0.015

7 0

3 years ago

Silva set up a dog-walking buisness. He earned $60 in June. He is projected to earn 110% more in July. How much is Silvia projec

Jlenok [28]

I think that gain of Silva, in July, is: 60+110100∗60=60+1110∗60=60+66=126$
so A.

6 0

3 years ago

Read 2 more answers

A television network is deciding whether or not to give its newest television show a spot during prime viewing time at night. If

musickatia [10]

Answer:

a. The test statistic for this hypothesis would be z=1.71

b. Critical value at α = 0.10: z=1.282

c. Reject H0, the television network should not keep its current lineup.

d. H0: p ≤ 0.50; HA: p > 0.50

Step-by-step explanation:

We have to performa an hypothesis test on a proportion.

The claim is that the proportion of viewers that prefer the new show is bigger than 50% (meaning that most viewers prefer the new show).

The null hypothesis will state that both shows have the same proportion.

Then, the null and alternative hypothesis are:

$H_0: \pi\leq0.50\\\\H_a: \pi>0.5$

The sample proportion is p=0.53

$p=X/n=438/827=0.53$

The standard error of the proportion is:

$\sigma_p=\sqrt{\dfrac{p(1-p)}{n}}=\sqrt{\dfrac{0.5*0.5}{827}}= 0.017$

Then, the z-statistic can be calculated as:

$z=\dfrac{p-\pi-0.5/n}{\sigma_p}=\dfrac{0.53-0.50-0.5/827}{0.017}=\dfrac{ 0.029 }{0.017} =1.706$

The critical value for a right tailed test at a significance level of 0.10 is zc=1.282. This value can be looked up in a standard normal distribution table.

As the statistic is bigger than the critical value, it lies in the rejection region. The null hypothesis is rejected. There is evidence to support the claim that the proportion of viewers which support the new show is larger than 0.50.

4 0

3 years ago

Compute 33(0.5) - 6(0.5) - 7/2.

lora16 [44]

Hi there! The answer is 10.

$33(0.5) - 6(0.5) - \frac{7}{2}$
We can use PEMDAS (Parenthesis, exponents, multiply, divide, add, subtract) to find our answer.

Since we cannot work inside the parenthesis in this question and since we don't have exponents, we can move on to multiplying.
$16.5 - 3 - \frac{7}{2}$

Our next step would be subtracting. To make the process of subtracting some easier, I'll first change the fraction into a decimal.
$16.5 - 3 - 3.5$

Finally subtract.
$13.5 - 3.5 = 10$

The answer is 10.
~ Hope this helps you!

5 0

3 years ago

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Consider a single spin of the spinner. Which events are mutually exclusive? Choose all that apply. a)landing on a shaded sector

denis23 [38]

Answer: the correct options are b and d.

Step-by-step explanation:

Let us first define what mutually exclusive events are. If two events are mutually exclusive, it means that they cannot happen at the same time. For example, getting a head and a tail at the same time are mutually exclusive.

Considering a single spin of the spinner, the events that are mutually exclusive are

b)landing on a shaded sector and landing on a 3. This is because 3 is unshaded. You can either land on 3 or an unshaded sector at a time

d)landing on an unshaded sector and landing on a number less than 2. This is because the numbers in the unshaded sectors are greater than 2.

3 0

3 years ago