Help please Algebra 2 B

Mathematics

1 answer:

NNADVOKAT [17]4 years ago

7 0

$- 2(3) + 5 \\ - 6 + 5 = - 1 \\ \\ - 2(4) + 5 \\ - 8 + 5 = - 3 \\ \\ - 2(5) + 5 \\ - 10 + 5 = - 5 \\ \\ - 2(6) + 5 \\ - 12 + 5 = - 7 \\ \\ - 1 + ( - 3) + ( - 5) + ( - 7) \\ = - 16$

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Find an equation of each line given one point and the slope : (4, 8); slope 8

Fudgin [204]

Step-by-step explanation:

in such a case the easiest approach might be using the point-slope form of a line equation :

y - y1 = m(x - x1)

with m being the slope, and (x1, y1) being a point on the line.

so, in our case that would be

y - 8 = 8(x - 4)

simplified this would be

y - 8 = 8x - 32

y = 8x - 24

FYI - this would be then the slope-intercept form (-24 would be the intercept point on the y-axis).

3 0

2 years ago

Based on the diagram, which expresses all possible lengths of segment AB? AB = 25 27 < AB < 81 AB = 85 AB< 27 or AB &gt

Thepotemich [5.8K]

The answer

according to the figure, we can solve this problem only by applying sines rule:
that is
sinA/a = sinB/b = sinC /c

As we observe, sin A /54 = sin B/27 = sin C/ c, and c = AB

besides, sinC > sinB > sinA , so the only answer possible is
<span>27 < AB < 81</span>

7 0

3 years ago

Read 2 more answers

The cost CC (in dollars) of making nn watches is represented by C=15n+85C=15n+85. How many watches are made when the cost is $38

dangina [55]

$\bf \stackrel{cost}{C}=15\stackrel{watches}{n}+85\qquad \boxed{C=385}\qquad \stackrel{cost}{385}=15n+85
\\\\\\
380=15n\implies \cfrac{380}{15}=n\implies \cfrac{76}{3}=n\implies 25\frac{1}{3}=n$

so, 25 whole watches and hmmmm just the wristband of another maybe.

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3 years ago

Tutorial Exercise A boat leaves a dock at 2:00 PM and travels due south at a speed of 20 km/h. Another boat has been heading due

ANTONII [103]

Answer:

Both the boats will closet together at 2:21:36 pm.

Step-by-step explanation:

Given that - At 2 pm boat 1 leaves dock and heads south and boat 2 heads east towards the dock. Assume the dock is at origin (0,0).

Speed of boat 1 is 20 km/h so the position of boat 1 at any time (0,-20t),

Formula : d=v*t

at 2 pm boat 2 was 15 km due west of the dock because it took the boat 1 hour to reach there at 15 km/h, so the position of boat 2 at that time was (-15,0)

the position of boat 2 is changing towards east, so the position of boat 2 at any time (-15+15t,0)

Formula : D= $\sqrt{(x2-x1)^2+(y2-y1)^2}$