Answer:
A. 5.16 s.
B. 5.66 s.
Step-by-step explanation:
A.
For a simple harmonic motion,
T = 2pi (sqrt * (l/g))
Given:
L1 = 3 cm
T1 = 4 s
L2 = 5 cm
T2 = ?
4 = 2pi*sqrt(3/g)
g = 7.4
At, L2,
T2 = 2pi*sqrt(5/7.4)
= 5.16 s.
B.
M1 = M1
M2 = 2*M1
For a simple harmonic motion,
T = 2pi (sqrt * (m/k))
4 = 2pi (sqrt * (M1/k))
M1/k = 0.405
Inputting the above values,
T2 = 2pi (sqrt * (2*M1/k))
= 2pi (sqrt * (2 * 0.405))
= 5.66 s.
Answer: 9000
Step-by-step explanation:
1000 nine times is equal to 9000
Rewrite the system of equations in matrix form.
![\begin{bmatrix}1&2&-2\\3&7&-1\\2&4&m\end{bmatrix} \mathbf x = \mathbf b](https://tex.z-dn.net/?f=%5Cbegin%7Bbmatrix%7D1%262%26-2%5C%5C3%267%26-1%5C%5C2%264%26m%5Cend%7Bbmatrix%7D%20%5Cmathbf%20x%20%3D%20%5Cmathbf%20b)
This system has a unique solution
so long as the inverse of the coefficient matrix
exists. This is the case if the determinant is not zero.
We have
![\det(\mathbf A) = m+4](https://tex.z-dn.net/?f=%5Cdet%28%5Cmathbf%20A%29%20%3D%20m%2B4)
so the inverse, and hence a unique solution to the system of equations, exists as long as m ≠ -4.
Answer:
g≤6
Step-by-step explanation:
Answer:
2268 in3
Step-by-step explanation: