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GaryK [48]
3 years ago
8

This problem models pollution effects in the Great Lakes. We assume pollutants are flowing into a lake at a constant rate of I k

g/year, and that water is flowing out at a constant rate of F km3/year. We also assume that the pollutants are uniformly distributed throughout the lake. If C(t) denotes the concentration (in kg/km3) of pollutants at time t (in years), then C(t) satisfies the differential equation dC dt = − F V C + I V where V is the volume of the lake (in km3). We assume that (pollutant-free) rain and streams flowing into the lake keep the volume of water in the lake constant. (a) Suppose that the concentration at time t = 0 is C0. Determine the concentration at any time t by solving the differential equation.

Mathematics
1 answer:
Alenkasestr [34]3 years ago
8 0

Answer:

C(t) = I/F [1 - e^(-Ft/V) ] + C₀e^(-Ft/V)

as t = 0 ; C(t) = 1/F

Explanation:

dC/dt) = (-F/V)*C+(I/V)

To make it easier to solve, let

Constants: I, V,F

Variables: C, t

workings and solution can be viewed below

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Sladkaya [172]

Answer:

C. (X-9)^9 + (y+9)^2= 16

D. (X-9)^2 + (y+5)^2= 9

Step-by-step explanation:

The formula for a circle is

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The 4th quadrant is where x is positive and y is negative

Add r to the y coordinate of the center and if it is still negative, the circle is still completely in the 4th quadrant

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The center is at 12,0 and the radius is sqrt(72) = 6sqrt(2)

This will be positive so it goes into the 1st quadrant

B. (X-2)^2 + (y+7)^2= 64

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C. (X-9)^9 + (y+9)^2= 16

The center is at 9,-9  and the radius is 4

-9+4 = -5  so it is completely in the 4th quadrant

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The center is at 9,-5 and the radius is 3

-5+3 = -2 so it is completely in the 4th quadrant

4 0
3 years ago
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2 years ago
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Answer:

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A) the only mistake is changing the mixed number to an improper fraction . 
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