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GaryK [48]
3 years ago
8

This problem models pollution effects in the Great Lakes. We assume pollutants are flowing into a lake at a constant rate of I k

g/year, and that water is flowing out at a constant rate of F km3/year. We also assume that the pollutants are uniformly distributed throughout the lake. If C(t) denotes the concentration (in kg/km3) of pollutants at time t (in years), then C(t) satisfies the differential equation dC dt = − F V C + I V where V is the volume of the lake (in km3). We assume that (pollutant-free) rain and streams flowing into the lake keep the volume of water in the lake constant. (a) Suppose that the concentration at time t = 0 is C0. Determine the concentration at any time t by solving the differential equation.

Mathematics
1 answer:
Alenkasestr [34]3 years ago
8 0

Answer:

C(t) = I/F [1 - e^(-Ft/V) ] + C₀e^(-Ft/V)

as t = 0 ; C(t) = 1/F

Explanation:

dC/dt) = (-F/V)*C+(I/V)

To make it easier to solve, let

Constants: I, V,F

Variables: C, t

workings and solution can be viewed below

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Name 2 semi circles<br><br><br>​
mart [117]

Answer:

Arc CDE and arc EAC.

Step-by-step explanation:

Semicircles are exactly one-half of a circle and are always equal to 180 degrees. Since line CE is a horizontal line, measuring 180 degrees, 2 semicircles can be arcs CDE and EAC because they equal half of the circle.

I hope this helps!

8 0
2 years ago
Tell whether each statement about the fraction 5/9 is correct. Choose yes or no
lions [1.4K]

B and C are correct, A and D are incorrect

5 0
3 years ago
A regulation football field is 300 feet by 160
igomit [66]

Answer:

366.7424164 feet

Step-by-step explanation:

330x160

Use pythag theorem

a²+b²=c²

330²+160²=c²

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5 0
2 years ago
Question 10 of 10
Nuetrik [128]

Answer:

x+9=4x-4

=) x -4x = -4-9

=) -3x = -13

=) x = 13/3

It is not the form of ax 2 +bx +c =0

8 0
3 years ago
(x-1)(x-3)(x+5)(x+7)=297
mihalych1998 [28]

First simplify the expression into polynomial form,

(x-1)(x-3)(x+5)(x+7)=297

x^4+8x^3-10x^2-104x+105=297

x^4+8x^3-10x^2-104x-192=0

Now factor into,

(x-4)(x+8)(x^2+4x+6)=0

Which means the solutions are,

x-4=0\implies\boxed{x_1=4}

x+8=0\implies\boxed{x_2=-8}

and then two complex solutions because determinant of the third factor D\lt0,

x^2+4x+6=0

x^2+4x+4=-2

(x+2)^2=-2\implies\boxed{x_3=i\sqrt{2}-2},\boxed{x_4=-i\sqrt{2}-2}

Hope this helps :)

5 0
3 years ago
Read 2 more answers
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