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soldi70 [24.7K]
3 years ago
15

One x-intercept for a parabola is at the point (1,0). Use the factor method to find the other x-intercept for the parabola defin

ed by this equation: y=-5x^2+15x-10
Mathematics
1 answer:
Hoochie [10]3 years ago
3 0
First simplify the equation of parabola y=-5x^2+15x-10 in the following way:
D=(15)^2-4\cdot (-5) \cdot (-10)=225-200=25, \\  \sqrt{D}=5, \\  x_{1,2} = \dfrac{-15\pm 5}{2\cdot(-5)} = 2, 1  \\ -5x^2+15x-10=-5(x-1)(x-2), \\ y=-5(x-1)(x-2).
You can see that if x=1 or x=2, then y=0. Two points of intersection with x-axis are (1,0) and (2,0).

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