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2 years ago

If you change the sign of a point’s y-coordinate, how will the location of the point change

Mathematics

2 answers:

Anton [14]2 years ago

5 0

It will reflect across the x axis

vampirchik [111]2 years ago

5 0

Why not experiment? Plot the point (2,7), Then change the y-coordinate's sign: (2,-7). Plot this new point. How did the location of (2.7) change when you changed the sign of the y-coordinate (7)?

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6. Emily rides her bike with a constant speed of

qaws [65]

Answer:

42 miles

Step-by-step explanation:

If it's a constant 12 miles per hour then it would be

12 mph x 3 hours = 36

then you would add that with the 1/2 hour for

12 mph x 1/2 hours = 6

36 + 6 = 42 miles traveled

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1 year ago

Find the circumference. Use 3.14 for n. r = 3 C = [?] ft = C=Td

VLD [36.1K]

Answer: 37.68 feet

Step-by-step explanation:

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2 years ago

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Solve the system of equations y = x + 5 and y = 5x - 11 using a graphical method.

tresset_1 [31]

You can use substitution for this.

x+5 = 5x -11

Combine like terms

16=4x

Divide 4 on both sides to isolate the x

x=4

Plug x=4 to one of the equations

y= 4 +5

Combine like terms

y=9

So the answer is A. (4,9)

I hope this helps you out a bunch hun :)

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2 years ago

Perform the indicated operation and write in standard form 5i+(-9-i)

antoniya [11.8K]

Since the sign before the parentheses is a + , we can just remove the parentheses.

5i + (-9 - i) = 5i - 9 - i = -9 + 4i

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2 years ago

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Yahoo creates a test to classify emails as spam or not spam based on the contained words. This test accurately identifies spam (

Amiraneli [1.4K]

Answer and Step-by-step explanation:

The computation is shown below:

Let us assume that

Spam Email be S

And, test spam positive be T

Given that

P(S) = 0.3

$P(\frac{T}{S}) = 0.95$

$P(\frac{T}{S^c}) = 0.05$

Now based on the above information, the probabilities are as follows

i. P(Spam Email) is

= P(S)

= 0.3

$P(S^c) = 1 - P(S)$

= 1 - 0.3

= 0.7

ii. $P(\frac{S}{T}) = \frac{P(S\cap\ T}{P(T)}$

$= \frac{P(\frac{T}{S}) . P(S) }{P(\frac{T}{S}) . P(S) + P(\frac{T}{S^c}) . P(S^c) }$

$= \frac{0.95 \times 0.3}{0.95 \times 0.3 + 0.05 \times 0.7}$

= 0.8906

iii. $P(\frac{S}{T^c}) = \frac{P(S\cap\ T^c}{P(T^c)}$

$= \frac{P(\frac{T^c}{S}) . P(S) }{P(\frac{T^c}{S}) . P(S) + P(\frac{T^c}{S^c}) . P(S^c) }$

$= \frac{(1 - 0.95)\times 0.3}{ (1 -0.95)0.95 \times 0.3 + (1 - 0.05) \times 0.7}$

= 0.0221

We simply applied the above formulas so that the each part could come

8 0

2 years ago