9514 1404 393
Answer:
Step-by-step explanation:
Let x and y represent the weights of the large and small boxes, respectively. The problem statement gives rise to the system of equations ...
x + y = 85 . . . . . combined weight of a large and small box
70x +50y = 5350 . . . . combined weight of 70 large and 50 small boxes
We can subtract 50 times the first equation from the second to find the weight of a large box.
(70x +50y) -50(x +y) = (5350) -50(85)
20x = 1100 . . . . simplify
x = 55 . . . . . . . divide by 20
Using this in the first equation, we can find the weight of a small box.
55 +y = 85
y = 30 . . . . . . . subtract 55
A large box weighs 55 pounds; a small box weighs 30 pounds.
(8x^2+5x+3)+(-5x^6-2x^5+4x^2-2x)=
8x^2+5x+3-5x^6-2x^5+4x^2-2x=
-5x^6-2x^5+(8-4)x^2+(5-2)x+3=
-5x^6-2x^5+4x^2+3x+3
Answer: Option B. -5x^6-2x^5+4x^2+3x+3
First, replace all variables with the given values.
12(9) + 9(2) + 2(12)
This should then equal 150, then the formula says to multiply this answer by 2. Doing so, should give a final answer of 300.
Answer:
357.46 meters squared
Step-by-step explanation:
16 x 12.2 x 1/2 = 97.6
12.2 x 10.6 = 64.66
97.6 x 3 = 292.8
292.8 + 64.66 = 357.46
Positions of 2, 5, 17 are not changed - so its not commutative property
