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raketka [301]
2 years ago
6

Can someone help me understand this pls? (Provide an explanation)

Mathematics
1 answer:
Tpy6a [65]2 years ago
3 0

Answer:

fales

Step-by-step explanation:

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It is a pyramid. a polygon meets with a polyhedron and make a pyramid
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3 years ago
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Suppose that 12% of test scores for the unit 1 test were above 85 and 8% were below 70. Assuming a normal
Doss [256]

Answer:

Mean = 78.2

Standard deviation = 5.8

Step-by-step explanation:

Mathematically z-score;

= (x-mean)/SD

From the question;

12% of test scores were above 85

Thus;

P( x > 85) = 12%

P(x > 85) = 0.12

Now let’s get the z-score that has a probability of 0.12

This can be obtained from the standard normal distribution table and it is = 1.175

Thus;

1.175 = (85 - mean)/SD

let’s call the mean a and the SD b

1.175 = (85-a)/b

1.175b = 85 - a

a = 85 - 1.175b ••••••••(i)

Secondly 8% of scores were below 70

Let’s find the z-score corresponding to this proportion;

We use the standard normal distribution table as usual;

P( x < 70) = 0.08

z-score = -1.405

Thus;

-1.405 =( 70-a)/b

-1.405b = 70-a

a = 70 + 1.405b ••••••(ii)

Equate the two a

70 + 1.405b = 85 - 1.175b

85 -70 = 1.405b + 1.175b

15 = 2.58b

b = 15/2.58

b = 5.81

a = 70 + 1.405b

a = 70 + 1.405(5.81)

a = 78.16

So mean = 78.2 and Standard deviation is 5.8

4 0
3 years ago
What value of x makes this equation true?-80=20+x​
Svet_ta [14]

Answer:

50 i think

Step-by-step explanation:

4 0
3 years ago
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Adult men have heights that a normally distributed with a mean of 69.5 inches and a standard deviation of 2.4 inches. Adult wome
Aliun [14]

Answer:

Step-by-step explanation:

From the information given:

For Adult Men

Mean \mu = 69.5

Standard deviation \sigma = 2.4

observed value X = 74

For Adult Women

Mean \mu = 63.8

Standard deviation \sigma = 2.6

observed value X = 70

Therefore ; the values for their z  scores can be obtained in order to determine who is more unusually tall within his or her respective sex

For Adult Men :

z = \dfrac{X- \mu}{\sigma}

z = \dfrac{74- 69.5}{2.4}

z = \dfrac{4.5}{2.4}

z = 1.875

For Adult Women :

z = \dfrac{X- \mu}{\sigma}

z = \dfrac{70- 63.8}{2.6}

z = \dfrac{6.2}{2.6}

z = 2.3846

Thus; we can conclude that , the women is more unusually tall within his or her respective sex

5 0
3 years ago
Trigonometry
quester [9]

Answer:

\frac{9 + 2 \sqrt{3} }{3} \\

Step-by-step explanation:

\cosec(30)  +  \cosec(60)  +  \cosec(90)  \\   \\  = 2 +  \frac{2}{ \sqrt{3} }  + 1 \\  \\  =  \frac{2 \sqrt{3 }  + 2}{ \sqrt{3} }  + 1 \\  \\  =  \frac{2 \sqrt{3}  + 2 +  \sqrt{3} }{ \sqrt{3} }  \\  \\  =  \frac{3 \sqrt{3}  + 2}{ \sqrt{3} }  \\  \\  = \frac{3 \sqrt{3}  + 2}{ \sqrt{3} }  \times  \frac{ \sqrt{3} }{ \sqrt{3} }  \\  \\  =  \frac{9 + 2 \sqrt{3} }{3}

4 0
3 years ago
Read 2 more answers
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