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4 years ago

What is the answer to 5+5(x+4)≤20?

2 answers:

7 0

$5+5\left( x+4 \right) \le 20\\ \\ 5\left\{ 1+\left( x+4 \right) \right\} \le 20\\ \\ \frac { 1 }{ 5 } \cdot 5\left\{ 1+\left( x+4 \right) \right\} \le 20\cdot \frac { 1 }{ 5 }$

$\ \\ 1+\left( x+4 \right) \le 4\\ \\ 1+x+4\le 4\\ \\ x+5\le 4\\ \\ x\le 4-5\\ \\ x\le -1$

sashaice [31]4 years ago

7 0

$5+5(x+4) \leq 20$

$5+5x+20 \leq 20$

$5+5x \leq 0$

$5(1+x) \leq 0$

$1+x \leq 0$

$x \leq -1$

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Write the equation of the line that passes through the points (8, -4) and (-2,5).

Sladkaya [172]

Answer:

The equation in the slope-intercept form will be:

Step-by-step explanation:

Given the points

(8, -4) and (-2, 5)

The slope between two points

$m=\frac{5-\left(-4\right)}{-2-8}$

$m=-\frac{9}{10}$

As the point-slope form is

$y-y_1=m\left(x-x_1\right)$

substituting the values m = -9/10 and (8, -4)

$y-\left(-4\right)=-\frac{9}{10}\left(x-8\right)$

Writing the line equation in the slope-intercept form

$y=mx+b$

where m is the slope and b is the y-intercept

so the equation in the slope-intercept form will be:

$y-\left(-4\right)=-\frac{9}{10}\left(x-8\right)$

$y+4=-\frac{9}{10}\left(x-8\right)$

subtract 4 from both sides

$y+4-4=-\frac{9}{10}\left(x-8\right)-4$

$y=-\frac{9}{10}x+\frac{16}{5}$

Therefore, the equation in the slope-intercept form will be:

$y=-\frac{9}{10}x+\frac{16}{5}$

7 0

3 years ago

Can someone help me please

Vinil7 [7]

Answer:

4 -> 1 -> 1/4 -> 1/16

8 0

3 years ago

2. Joel can type 197 words per minute if she types at the same rate, how many words can

Andre45 [30]

I believe it is 6,895. I just multiplied by 197 by 35

4 0

3 years ago

Consider a binomial experiment with n = 10 and p = 0.10. (a) Compute f(0). If required, round your answer to four decimal places

ss7ja [257]

Answer:

(a) The value of f (0) is 0.3487.

(b) The value of f (2) is 0.1937.

(d) The value of P (X ≥ 1) is 0.6513.

(e) The value of E (X) is 1.

(f) The value of V (X) is 0.9 and σ is 0.9487.

Step-by-step explanation:

The random variable X follows a Binomial distribution with parameter n = 10 and p = 0.10.

The probability mass function of X is:

$P(X=x)={10\choose x}0.10^{x}(1-0.10)^{10-x};\ x=0,1,2,3...$

(a)

Compute the value of f (0) as follows:

f (0) = P (X = 0)

$={10\choose 0}0.10^{0}(1-0.10)^{10-0}\\=1\times 1\times 0.348678\\=0.348678\\\approx0.3487$

Thus, the value of f (0) is 0.3487.

(b)

Compute the value of f (2) as follows:

f (2) = P (X = 2)

$={10\choose 2}0.10^{2}(1-0.10)^{10-2}\\=45\times 0.01\times 0.43047\\=0.1937115\\\approx0.1937$

Thus, the value of f (2) is 0.1937.

(c)

Compute the value of P (X ≤ 2) as follows:

P (X ≤ 2) = P (X = 0) + P (X = 1) + P (X = 2)

$=\sum\limits^{0}_{2} {{10\choose x}0.10^{x}(1-0.10)^{10-x}}\\=0.3487+0.3874+0.1937\\=0.9298$

Thus, the value of P (X ≤ 2) is 0.9298.

(d)

Compute the value of P (X ≥ 1) as follows:

P (X ≥ 1) = 1 - P (X < 1)

= 1 - P (X = 0)

= 1 - 0.3487

= 0.6513

Thus, the value of P (X ≥ 1) is 0.6513.

(e)

Compute the expected value of X as follows:

$E(X)=n\times p$

$=10\times 0.10\\=1$

Thus, the value of E (X) is 1.

(f)

Compute the variance of X as follows:

$V(X)=np(1-p)$

$=10\times 0.10\times (1-0.10)\\=0.90$

Compute the standard deviation of X as follows:

$SD(X)=\sqrt{V(X)}$

$=\sqrt{0.90}\\=0.94868\\\approx0.9487$

Thus, the value of V (X) is 0.9 and σ is 0.9487.

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4 years ago

I need an answer and explanation for both but it’s alright if you can answer one of em

Tanzania [10]

I did first one only (roughy) but hope it helps

6 0

4 years ago