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3 years ago

the same digits are used for the expression 2^5 and 5^2 explain how to compare the value of the expressions

Mathematics

1 answer:

iris [78.8K]3 years ago

6 0

the value of 2⁵ is greater than the value of 5² because 2⁵ is equal to 32 then the value of 5² is equal to 25.

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4 years ago

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nika2105 [10]

Answer:

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Step-by-step explanation:

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3 years ago

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LuckyWell [14K]

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3 years ago

Read 2 more answers

If g (x) = 1/x^2 then g (x+h) - g (x)/h

nignag [31]

$\bf g(x)=\cfrac{1}{x^2}~\hspace{5em}\cfrac{g(x+h)-g(x)}{h}\implies \cfrac{\frac{1}{(x+h)^2}-\frac{1}{x^2}}{h} \\\\\\ \textit{using the LCD of }(x+h)^2(x^2)\qquad \cfrac{\frac{x^2-(x+h)^2}{(x+h)^2(x^2)}}{h}\implies \cfrac{x^2-(x+h)^2}{h(x+h)^2(x^2)} \\\\\\ \cfrac{x^2-(x^2+2xh+h^2)}{h(x+h)^2(x^2)}\implies \cfrac{\underline{x^2-x^2}-2xh-h^2}{h(x+h)^2(x^2)}\implies \cfrac{-2xh-h^2}{h(x+h)^2(x^2)}$

$\bf \cfrac{\underline{h}(-2x-h)}{\underline{h}(x+h)^2(x^2)}\implies \cfrac{-2x-h}{(x+h)^2(x^2)}\implies \cfrac{-2x-h}{(x^2+2xh+h^2)(x^2)} \\\\[-0.35em] ~\dotfill\\\\ ~\hfill \cfrac{-2x-h}{x^4+2x^3h+x^2h^2}~\hfill$

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3 years ago