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3 years ago

Which plane figure generates a cylinder when it rotates about the dashed line?

Mathematics

1 answer:

Marina CMI [18]3 years ago

7 0

I am not exactly sure, but I am almost positive it is a spere

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What’s the value of x?

lozanna [386]

x=13 because you put all of them in an equation and set them equal to 180 bc that is how many degrees are in a triangle so it would be 6x+19+5x-15+3x-6=180 and then you solve the equation so it would be 14x-2=180 then you would add to to both side which would cancel out on the left and make 182 on the right then divide 182 by 14 and you get 13.

6 0

3 years ago

I need help! It didn’t explain this in the study guide!!!

attashe74 [19]

all you need to do is subtract. 133-87 which is 46 so <AKD is 46deg

6 0

4 years ago

Read 2 more answers

30 points plzzz!!!!!!

irinina [24]

Answer:

Step-by-step explanation:

9:8 = 4x+2:4x

36x = 32x + 16

x = 4

6 0

2 years ago

This is the last one lol . find the value of x

netineya [11]

Answer:

Step-by-step explanation:

Since these 115 and the angle adjacent to x are alternate interior angles, then that angle is equal to 115. That angle and x add up to 180, so we do 180-115, which is equal to 65.

7 0

4 years ago

Find the volume V of the solid obtained by rotating the region bounded by the given curves about the specified line. Y = (4/9) x

frez [133]

Answer:

V = 8.06 cubed units

Step-by-step explanation:

You have the following curves:

$y_1=\frac{4}{9}x^2=f(x)\\\\y_2=\frac{13}{9}-x^2=g(x)$

In order to calculate the solid of revolution bounded by the previous curves and the x axis, you use the following formula:

$V=\pi \int_a^b [(g(x))^2-(f(x))^2]dx$ (1)

To determine the limits of the integral you equal both curves f=g and solve for x:

$f(x)=g(x)\\\\\frac{4}{9}x^2=\frac{13}{9}-x^2\\\\\frac{4}{9}x^2+x^2=\frac{13}{9}\\\\\frac{13}{9}x^2=\frac{13}{9}\\\\x=\pm 1$

Then, the limits are a = -1 and b = 1

You replace f(x), g(x), a and b in the equation (1):

$V=\pi \int_{-1}^{1}[(\frac{13}{9}-x^2)^2-(\frac{4}{9}x^2)^2]dx\\\\V=\pi \int_{-1}^1[\frac{169}{81}-\frac{26}{9}x^2+x^4-\frac{16}{81}x^4]dx\\\\V=\pi \int_{-1}^1 [\frac{169}{81}-\frac{26}{9}x^2+\frac{65}{81}x^4]dx\\\\V=\pi [\frac{169}{81}x-\frac{26}{27}x^3+\frac{65}{405}x^5]_{-1}^1\\\\V\approx8.06\ cubed\ units$

The volume of the solid of revolution is approximately 8.06 cubed units

8 0

4 years ago