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Tanzania [10]
3 years ago
8

How to draw a model of 3/10

Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0
Draw a pizza with 10 slices and shade 3 slices
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1. 6x + 2y = -12
8090 [49]

Answer:

J71763eua8w8w8us

Nakshatra w

Nskd8w8

I2991992

3 0
3 years ago
Show me the break down for 52divide into 5256
Blizzard [7]
It is in all 0.0098934551 in all in total
4 0
3 years ago
How many terms are in the arithmetic sequence shown below?<br>15, 7, -1, -9...,-225
NemiM [27]
We know that

We can write an Arithmetic Sequence as a rule:

<span>an = a1 + d(n−1)</span>

where

<span>a1 = the first term
<span>d =the "common difference" between terms

in this problem
a1=15  a2=7  a3=-1  a4=-9  .....    an=-225
d=a2-a1  
d=7-15-----> d=-8

</span></span>an = a1 + d(n−1)
for
an=-225
d=-8
a1=15
find n
-225=15+(-8)*(n-1)--> (n-1)=[-225-15]/-8----> n-1=30---> n=30+1---> n=31

the answer is
31

3 0
3 years ago
a tree 20 feet tall with a circumference of 3 ft has a vine wound around 7 times. How long is the vine?
FinnZ [79.3K]

If the tree is 20 feet tall with circumference 3 feet then the length of  vince is around 21 feet.

Given the height of tree is 20 feet and the circumference of tree is 3 feet.

We have to find the length of vine.

Circumference is the perimeter of a circular object. Because the trunk of a tree is in shape of circle so the perimeter of the trunk is 2πr.

We have been given the circumference of tree be 3 feet.

Circumference=2πr

Because vine is 7 times the circumference so the length of vine being:

Length of vine=7*3

=21 feet.

Hence if the tree is 20 feet tall with circumference 3 feet then the vince is around 21 feet long.

Learn more about circumference at brainly.com/question/20489969

#SPJ1

4 0
2 years ago
Read 2 more answers
An experiment was conducted to investigate whether there is a difference in mean bag strengths for two different brands of paper
Elanso [62]

Answer:

A two-sample t-test for a difference between sample means

Step-by-step explanation:

<u>Explanation</u>:-

A random sample of 50 bags from each of Brand X and Brand Y was selected

Given two sample sizes n₁ and n₂

Each bag was held from its rim, and one-ounce weights were dropped into the bag one at a time from the same height until the bag ripped

mean of ounces the first sample = x⁻

mean of the  second sample =y⁻

Given data one-ounce weights were dropped into the bag one at a time from the same height until the bag ripped

Standard deviation of the first sample = S₁

Standard deviation of the second sample = S₂

Now we use t - distribution for a difference between the means

t = \frac{x^{-}  -y^{-} }{\sqrt{S^{2}(\frac{1}{n_{1} }  +\frac{1}{n_{2} } } }

where

S^{2} = \frac{n_{1} S_{1} ^{2} +n_{2}S_{2} ^{2}  }{n_{1} +n_{2} -2 }

Degrees of freedom γ = n₁ +n₂ -2

3 0
3 years ago
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