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Svetach [21]
3 years ago
15

A 35 pound dog eats an average of 2 1/2 cups of dry dog food a day. If you assume that there is a relationship between size and

consumption, the amount of food an animal eats, how much food does a 70 pound dog eats? if your dog is 140 pounds, and you have 7 1/2 cups of food, do you have enough? explain your answer. Challenge: An 8 pound cat eats an average of 1/2 cup of dry food. Per pound, which type of animal eats more, cat or a dog? Explain your answer.
Mathematics
1 answer:
zimovet [89]3 years ago
8 0
70 / 35 = 2
So the 70 pound dog weights double the weight of the 35 pound dog, so he will eat twice as much.

2 x 2.5 = 5 cups

Meaning he will eat 5 cups of dry dog food a day.

By the same logic a 140 pound dog would have to eat twice what a 70 pound dog eats, that is 10 cups of dry dog food a day, so 7 1/2 cups are not enough.

Challenge: per pound a dog eats more than a cat. Since you know a 140 pound dog eats 10 cups, you can dive 140 by 10, to find out that each cup feeds 14 pounds, so half a cup would be the amount of food to feed a 7 pound dog, meaning that a dog weighing 1 pound less than a 8 pound cat would need the same amount of food, so it eats more than a cat.

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The final grade in an algebra course is based on a weighted average - homework counts 10%, quizzes count 15%, tests count 50%, a
tresset_1 [31]

Answer:  74

<u>Step-by-step explanation:</u>

Homework +    Quiz    +   Test    + Final Exam = 70

  67(10%)    + 62(15%)  + 71(50%) +    x(25%)    = 70

   6.7           +    9.3      +   35.5    +      0.25x     = 70

                                                      51.5 + 0.25x = 70

                                                                 0.25x = 18.5

                                                                        x = 74

The minimum score is 74.

8 0
3 years ago
Read 2 more answers
Quadrilaterals WXYZ and W"X"Y"Z"are similar. Identify the type of reflection
Anna71 [15]

Answer:

B) To obtain quadrilateral W'X'Y"Z" quadrilateral WXYZ is reflected across

the x-axis and dilated with a scale factor of 1/2

Step-by-step explanation:

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, rotation, translation and dilation.

If a point A(x, y) is reflected across the x axis the new point is at A'(x, -y)

Dilation is the enlargement or reduction in the size of a figure by a scale factor. If a point A(x, y) is dilated by a scale factor of k about the center of origin, the new point is at A'(kx, ky).

The vertex of Quadrilaterals WXYZ is at W(-6, 8), X(-2, 8), Y(-2, 2), Z(-6, 8) while the vertex of Quadrilaterals W"X"Y"Z" is at W"(-3, -4), X"(-2, -4), Y"(-1, -1), Z"(-3, -4)

If quadrilateral WXYZ is reflected across  the x-axis, the new coordinates would be at W'(-6, -), X'(-2, -8), Y'(-2, -2), Z'(-6, -8). If the quadrilateral is then dilated with a scale factor of 1/2, the new point is at W"(-3, -4), X"(-2, -4), Y"(-1, -1), Z"(-3, -4)

5 0
3 years ago
Wendy and two friends went out to eat and decided they would split the bill. The total bill was 35.40. They also decided to leav
marta [7]

Answer:

14.16

Step-by-step explanation:

we first calculate the total amount of money paid, which is 35.40 plus 20%, we use this calculation:

35.40×1.20 = 42.48

now, this amount is split to 3 people, so:

42.48/3 = 14.16

and that is our answer

8 0
2 years ago
A truck is leaving a post office and heading out to deliver mail. The table shows the truck's distance d from the post office at
zalisa [80]

Answer:

eliver mail. The table shows the truck's distance d from the post office at time t. Calculate the average rate of change over the interval from 8 to 15 minutes. t(min) d (km) 0 0 8 7 11 11 15 14 22 16 (1 point) The rate of change is about 0.8 kilometers per minute. The rate of change is 7 kilometers

7 0
3 years ago
I NEED HELP PLEASE, THANKS! :)
NISA [10]

Answer:   \bold{b)\quad \dfrac{2\pi}{3},\dfrac{4\pi}{3},0}

<u>Step-by-step explanation:</u>

Note the following identities: tan² x = sec²x - 1

                                                 \sec x=\dfrac{1}{\cos}

tan² x + sec x = 1

(sec² x -1) + sec x = 1

sec² x + sec x - 2 = 0

(sec x + 2)(sec x - 1) = 0

sec x + 2 = 0     sec x - 1 = 0

sec x = -2          sec x = 1

\dfrac{1}{\cos x}=-2\qquad \dfrac{1}{\cos x}=1\\\\\cos x=-\dfrac{1}{2}\qquad \cos x=1\\\\x=\dfrac{2\pi}{3}, \dfrac{4\pi}{3}\qquad x=0

8 0
3 years ago
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