1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
aleksandr82 [10.1K]
2 years ago
12

HELPPPPPP PLZZZZ OMG :(

Mathematics
2 answers:
vfiekz [6]2 years ago
5 0

Answer:

1. C

2. A

Step-by-step explanation:

guapka [62]2 years ago
3 0
The answer is A for the first one the second one is B -1
You might be interested in
Help plsplspls !! :)
vagabundo [1.1K]

Answer:

I want to say it's -69/100

Step-by-step explanation:

Hope that helps!

3 0
2 years ago
**50 Points Possible** I NEED URGENT HELP <br>please provide a graph
Elina [12.6K]

Answer:

See below.

Step-by-step explanation:

1)

For Ben's social media post, we are told that it was initially shared to only 2 people. However, each of those shares it with 3 people. In other words, Ben's post triples every day. This means that the rate of growth is 3. Thus, Ben's post as an exponential function is:

f(x)=2(3)^x

The 2 represents the initial amount at day 0, and the 3 represents the rate at which the post grows each day.

2)

Similarly, Carter's post was originally sent to 10 people. However, each of the 10 shares it with two others. Therefore, it doubles each day. Thus, the rate is 2. So, Carter's exponential function is:

f(x)=10(2)^x

The 10 represents the initial amount while the 2 represents the rate.

3)

I've use Desmos to graph the functions. Refer to the picture attached. Red is Amber, blue is Ben, and green is Carter.

4)

To find out the number of shares each student's post will receive on day 3 and day 10, simply plug the numbers into the functions. Therefore:

For Amber:

Day 3:

f(3)=3(4)^3=192

Day 10:

f(10)=3(4)^{10}=3,145,728

For Ben:

Day 3:

f(3)=2(3)^3=54

Day 10:

f(10)=2(3)^{10}=118,098

And for Carter:

Day 3:

f(3)=10(2)^3=80

Day 10:

f(10)=10(2)^{10}=10,240

5)

Amber's new graph of:

f(x)=3(4)^x+45

will be a shifted version of her original graph. The new graph will be shifted upwards by 45 units. However, since the 45 is not affected by the x in any way, the change will be minuscule. For instance, her number of shares on day 10 of the old graph is 3,145,728. Even with the additional 45, it will just be: 3,145,773. With enough days, the additional number becomes trivial.

6)

On the 10th day, Amber's post was shared almost 3 million times, while Ben's was shared "only" 118,098 times and Carter's with 10,240. Undoubtedly, Amber's post was the fastest.

7)

If you want to most shares as possible, choose Amber with fewer friends initially but more shares. This is because the exponential potential of a number even just a bit higher is insane. For instance, 3^10 (Ben's rate at 10th day) is only 59,049 while Amber's rate will be 4^10 which is 1,048,576. Amber's number is almost 18 times higher than Ben's. Even if Ben's initial number was say 1,000 or even 1,000,000, Amber would catch up rather quickly. Therefore, the rate is the quintessential part of an exponential growth function.

5 0
3 years ago
Beer shelf life is a problem for brewers and distributors because when beer is stored at room temperature, its flavor deteriorat
mr_godi [17]

Answer:

As the calculated value of t =2.1698 is greater than t (0.05,11) = 1.796 reject H0 . It means  chosen bottles stored for a month convince you that the mean furfuryl ether content exceeds the taste threshhold.

Step-by-step explanation:

We formulate our null and alternative hypotheses as

H0 u≤ 6 ug     Ha : u > 6 ug

The significance level ∝ = 0.05

The test statistic used is

t = X` - u / s/ √n

which if H0 is true, has the students' t test with n-1 = 11 degrees of freedom.

The critical region t > t (0.05,11) = 1.796

We compute the t value from the data

Xi               Xi²

8.92         79.5664

6.99          48.8601

5.54          30.6916

5.73           32.8329

6.38           40.7044

5.51            30.3601

6.45           41.6025

7.50           56.25

8.48           71.9104

5.56          30.9136

6.90          47.61

<u>6.46          41.7316          </u>

<u>80.42         553.0336</u><u>      </u>

<u />

Now x` = ∑x/ n = 80.42/12 = 6.70

S²= 1/n-1 ( ∑(xi- x`)²= 1/11 ( 553.034 - (80.42)²/12)

= 1/11 (553.034-538.948) = 1.2805

s= 1.1316

Putting the values in the test statistics

t = X` - u / s/ √n = 6.70- 6 / 1.1316 / √12

= 2.1698

The critical region t > t (0.05,11) = 1.796

As the calculated value of t =2.1698 is greater than t (0.05,11) = 1.796 reject H0 . It means  chosen bottles stored for a month convince you that the mean furfuryl ether content exceeds the taste threshhold.

6 0
3 years ago
Sandy works at a clothing store. She makes $9 per hour plus earns 10% commission on her sales. She worked 80 hours over the last
irina [24]
D. $720 is the answer
8 0
3 years ago
What question is answered by the equation d=4 (32)
Doss [256]
By this equation:  d = 4(32), we know what d equals, which means we have the value of d. 

d= 4*32
d = 128
5 0
3 years ago
Other questions:
  • A culture of bacteria has an initial population of 22000 bacteria and doubles every 5 hours. Using the formula P t = P 0 ⋅ 2 t d
    13·1 answer
  • Is 8y=32 a true statement or false statement or not a statement?
    15·1 answer
  • Write the equation in slope-intercept form. What are the slope and y-intercept?<br> -10x +11y = -6
    15·1 answer
  • Ross and 5 of his friends are going kayaking. They rented 6 kayaks for $420. Then they bought food for all 6 people, which cost
    14·1 answer
  • Find domain and range for f(x)=x^2-2x+2
    12·1 answer
  • Find two consecutive odd integers whose sum is 16​
    6·1 answer
  • A(n) _________________ of a probability experiment is the collection of all outcomes possible. prediction set event set sample s
    8·1 answer
  • PLZZ I NEED TO KNOW NOW 30 POINTS!!
    8·1 answer
  • -4(y-2)=12 help please​
    8·2 answers
  • -4(-2x + 5) + 2x + 3 =-11
    7·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!