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inn [45]
3 years ago
13

MAX 100 POINTS / HELP ASAP THIS IS VERY IMPORTANT FOR MY GRADE / WILL MARK BRAINLIEST IF RIGHT.---------------------------------

-------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------Drag each label to the correct location on the table. Each label can be used more than once, but not all labels will be used.Simplify the given polynomials. Then, classify each polynomial by its degree and number of terms.
Polynomial 1: (x-1/2)(6x+2)
Polynomial 2: (7x^2+3x)-1/3(21x^2-12)
Polynomial 3: 4(5x^2-9x+7)+2(-10x^2+18x-13)

Mathematics
1 answer:
AlekseyPX3 years ago
4 0

Answer:

Polynomial 1:

  • Simplified Form: 6x^2 - x - 1
  • Name by Number of Terms: trinomial

Polynomial 2:

  • Name by Degree: linear
  • Name by Number of Terms: binomial

Polynomial 3:

  • Simplified Form: 2
  • Name by Degree: constant

Step-by-step explanation:

Polynomial 1:

(x-1/2)(6x+2)

6x^2 - 3x + 2x - 1

6x^2 - x - 1

It has 3 terms, so it's a trinomial.

Polynomial 2:

There is one term with x and x is raised to the first degree, so it's linear.

There are 2 terms, so it's a binomial.

Polynomial 3:

4(5x^2-9x+7)+2(-10x^2+18x-13)

20x^2 - 36x + 28 -20x^2 + 36x - 26

28 - 26

2

Since there are no variables and the answer is just 2, it's a constant.

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A set average city temperatures in August are normally distributed with a mean of 21.25 degrees Celsius and a standard deviation
Ainat [17]

Answer:

The proportion of temperatures that lie within the given limits are 10.24%

Step-by-step explanation:

Solution:-

- Let X be a random variable that denotes the average city temperatures in the month of August.

- The random variable X is normally distributed with parameters:

                           mean ( u ) = 21.25

                           standard deviation ( σ ) = 2

- Express the distribution of X:

                           X ~ Norm ( u , σ^2 )

                           X ~ Norm ( 21.25 , 2^2 )

- We are to evaluate the proportion of set of temperatures in the month of august that lies between 23.71 degrees Celsius and 26.17 degrees Celsius :

                           P ( 23.71 < X < 26.17 )

- We will standardize our limits i.e compute the Z-score values:

                          P (  (x1 - u) / σ < Z < (x2 - u) / σ )

                          P (  (23.71 - 21.25) / 2 < Z < (26.17 - 21.25) / 2  )

                          P ( 1.23 < Z < 2.46 ).

- Now use the standard normal distribution tables:

                          P ( 1.23 < Z < 2.46 ) = 0.1024

- The proportion of temperatures that lie within the given limits are 10.24%

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3 years ago
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Evaluate the expression 4x^3 for each value of x<br> 1 2, and 1/2<br> help me, plz
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Answer:

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Step-by-step explanation:

4 0
3 years ago
PLEASE HELPPP!!! THANK YOU SOO MUCH ILY!!!!!!!
MissTica

Answer:

1) Variables = 11a , 4a

  Constants = 0

  Coefficients = 11 , 4

2) Variables =  3x , 7x

   Constants = 6 , -4

   Coefficients = 3 , 7 , 6 , -4

3) Variables = -12m , +4m

   Constants = -3 , 16

   Coefficients = -12 , 4 , -3 , 16

4) Variables = 6k , k

   Constants = -4 , -2

   Coefficients = 6 , 1 , -4 , -2

5) Variables = -5p , -2p

   Constants = 3 , 13

   Coefficients = -5 , -2 , 3 , 13

6) Variables = -10r , -r , -6r

   Constants = 11

   Coefficients = -10 , -1 , -6 , 11

7) Variables = -5n

   Constants = 19 , -8 , 14

   Coefficients = -5 , 19 , -8 , 14

8) Variables = 13y , -2y

   Constants = 18 , -5

   Coefficients = 13 , -2 , 18 , -5

9) Variables = 8a , 3a , -7b , -2b

   Constants = 1

   Coefficients = 8 , 3 , -7 , -2 , 1

10) Variables = 11x , 2x , -4y

   Constants = 8

   Coefficients = 11 , 2 , -4 , 8

Step-by-step explanation:

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