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katen-ka-za [31]
3 years ago
14

A coin is tossed 7 times. What is the probability that the number of heads obtained will be between 2 and 7 inclusive? Express y

our answer as a fraction or a decimal number rounded to four decimal places.
Mathematics
1 answer:
Marina CMI [18]3 years ago
5 0

Answer:

0.9375

Step-by-step explanation:

Given the following :

Number of coin tosses = 7

Probability that number of heads obtained will be between 2 and 7 inclusive?

x = 2,3,4,5,6,7

Probability (P) = number of required outcomes / total possible outcomes

For a coin toss = 1 Head (H), 1 tail (T)

P(H) = 1 / 2

P(X) = C(7,x) * (1/2)^7

P(X) = C(7, x) / 0.5^-7

P(X) = [C(7,2) + C(7, 3)+ C(7,4) +C(7,5) + C(7,6) +C(7,7)] / 128

P(X) = (21 + 35 + 35 + 21 + 7 + 1) / 128

P(X) = 120 / 128

P(X) = 0.9375

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Step-by-step explanation:

We want to find the Riemann Sum for \int\limits^3_1 {9-x^2} \, dx with 4 sub-intervals, using right endpoints.

A Riemann Sum is a method for approximating the total area underneath a curve on a graph, otherwise known as an integral.

The Right Riemann Sum is given by:

\int_{a}^{b}f(x)dx\approx\Delta{x}\left(f(x_1)+f(x_2)+f(x_3)+...+f(x_{n-1})+f(x_{n})\right)

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f\left(x_{2}\right)=f\left(2\right)=5=5

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Next, we use the Right Riemann Sum formula

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