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3 years ago

Bruce walks 34 mile in 15 hour. What is his speed in miles per hour?

Mathematics

1 answer:

erastova [34]3 years ago

3 0

Answer:

S=D/T

34/15=2.26 mph

Step-by-step explanation:

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-3x + 18 = 7x solve

Harman [31]

Answer:

refer to the attachment

Step-by-step explanation:

hope that helps

3 0

2 years ago

Read 2 more answers

Choose the graph of the solution to this inequality.

Dmitriy789 [7]

Answer:

we can translate the given statement into-8 ≥ -5x + 2 > -38.

In this case, we can dissect the inequality into two parts:

-8 ≥ -5x + 2 and -5x + 2 > -38

Step-by-step explanation:

-8 ≥ -5x + 2 5x ≥ 10x ≥ 2 (closed dot)

-5x + 2 > -38 5x < 40x < 8 (open dot)

The answer then is c) number line with a closed dot on 2 and an open dot on 8 and shading in between

8 0

2 years ago

Find the value of the rectangular prism

Ainat [17]

27.

Volume = length*width*height
So 3*3*3=27

6 0

2 years ago

Overview Park has a picnic area and a playground, as shown in the diagram below. What is the area of the playground, in square f

laiz [17]

Answer:

Hi,

Step-by-step explanation:

The playground 's area is the difference of 2 squares:

20²-10²=(20+10)*(20-10)=30*10=300 (ft²)

7 0

1 year ago

Read 2 more answers

Choose the answer that validates that the rate of change is constant by showing that the ratios of the two quantities are propor

docker41 [41]

Given:

The table of values is

Number of Students : 7 14 21 28

Number of Textbooks : 35 70 105 140

To find:

The rate of change and showing that the ratios of the two quantities are proportional and equivalent to the unit rate.

Solution:

The ratio of number of textbooks to number of students are

$\dfrac{35}{7}=5$

$\dfrac{70}{14}=5$

$\dfrac{105}{21}=5$

$\dfrac{140}{28}=5$

All the ratios of the two quantities are proportional and equivalent to the unit rate.

Let y be the number of textbooks and x be the number of students, then

$\dfrac{y}{x}=k$

Here, k=5.

$\dfrac{y}{x}=5$

$y=5x$

Hence the rate of change is constant that is 5.

8 0

2 years ago