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kompoz [17]
4 years ago
7

Will give brainliest answer

Mathematics
2 answers:
lidiya [134]4 years ago
7 0
The square root of 10 because

sqrt(10) ^2 * 3.14 =

10*3.14 = 31.4
dmitriy555 [2]4 years ago
7 0

Answer:

78.4 square units

Step-by-step explanation:

First we will find the radius of the circle by using circumference formula of circle.

c = 2\pi \: r \\ 31.4 =  2 \times 3.14 \times r \\  \\ r =  \frac{31.4}{2 \times 3.14}  \\  \\ r =  \frac{3140}{2 \times 314}  \\  \\ r =  \frac{10}{2}  \\  \\ r = 5 \: units \\  \\ area \: of \: circle = \pi {r}^{2}  \\  = 3.14 \times  {5}^{2}  \\  = 3.14 \times 25 \\  = 78.5 \:  {units}^{2}  \\

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3 years ago
In Exercises 5-7, find all the exact t-values for which the given statement is true,
bearhunter [10]

Answer:  See Below

<u>Step-by-step explanation:</u>

NOTE: You need the Unit Circle to answer these (attached)

5) cos (t) = 1

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Answer: at 0π (0°) and all rotations of 2π (360°)

In radians:     t = 0π + 2πn

In degrees:   t = 0° + 360n

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6)\quad sin (t) = \dfrac{1}{2}

Where on the Unit Circle does   sin = \dfrac{1}{2}

<em>Hint: sin is only positive in Quadrants I and II</em>

\text{Answer: at}\  \dfrac{\pi}{6}\ (30^o)\ \text{and at}\ \dfrac{5\pi}{6}\ (150^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{\pi}{6} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{6} + 2\pi n

In degrees:    t = 30° + 360n  and  150° + 360n

******************************************************************************

7)\quad tan (t) = -\sqrt3

Where on the Unit Circle does    \dfrac{sin}{cos} = \dfrac{-\sqrt3}{1}\ or\ \dfrac{\sqrt3}{-1}\quad \rightarrow \quad (1,-\sqrt3)\ or\ (-1, \sqrt3)

<em>Hint: sin and cos are only opposite signs in Quadrants II and IV</em>

\text{Answer: at}\  \dfrac{2\pi}{3}\ (120^o)\ \text{and at}\ \dfrac{5\pi}{3}\ (300^o)\ \text{and all rotations of}\ 2\pi \ (360^o)

\text{In radians:}\ t = \dfrac{2\pi}{3} + 2\pi n \quad \text{and}\quad \dfrac{5\pi}{3} + 2\pi n

In degrees:    t = 120° + 360n  and  300° + 360n

4 0
3 years ago
The perimeter of a rectangular playgroundis 46m. If the length of the park is 7m, what is the width of the park ?
Vikki [24]

Answer:

32

Step-by-step explanation:

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3 years ago
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3 years ago
Unit 8: Right Triangles &amp; Trigonometry<br> Homework 2: Special Right Triangles
Kamila [148]

Answer:

17. z=39/sin45=78/\sqrt{2}

    y=39/tan60=39/\sqrt{3}

    x=y/sin60=78/\sqrt{3}

19. x=6\sqrt{3}/tan60=6

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    z=\sqrt{2}y=12\sqrt{2}

Step-by-step explanation:

17.

because:sin45=39/z    

so:     z=39/sin45=78/\sqrt{2}

then: tan60=39/y

so:    y=39/tan60=39/\sqrt{3}

last:  sin60=y/x

so:    x=y/sin60=78/\sqrt{3}

19.

because: tan60=6\sqrt{3}/x

so:            x=6\sqrt{3}/tan60=6

then:        sin30=x/y

so:            y=x*sin30=2x=12

last:          sin45=y/z

so:            z=sin45*y=\sqrt{2}y=12\sqrt{2}

   

4 0
3 years ago
Read 2 more answers
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