Plug in both x and y values into the equation.
4(5) + 4
20 + 4
24
24 is your answer. I hope this helps!
Answer:
1 over 32
Step-by-step explanation:
you multiply 3 by 18 to get 64 then simplify by dividing by 2
To find the product of (4x-5y)^2,
we can rewrite the problem as:
(4x-5y)(4x-5y) (two times because it is squared)
Now, time to use that old method we learned in middle school:
FOIL. (Firsts, Outers, Inners, and Lasts)
FOIL can help us greatly in this scenario.
Let's start by multiplying the 'Firsts' together:
4x * 4x = <em>16x^2</em>
Now, lets to the 'Outers':
4x * -5y = <em>-20xy</em>
Next, we can multiply the 'Inners':
-5y * 4x = <em>-20xy</em>
Finally, let's do the 'Lasts':
-5y * -5y = <em>25y</em>^2
Now, we can take the products of these equations from FOIL and combine like terms. We have: 16x^2, -20xy, -20xy, and 25y^2.
-20xy and -20xy make -40xy.
The final equation (product of (4x-5y)^2) is:
16x^2 - 40xy + 25y^2
Hope I helped! If any of my math is wrong, please report and let me know!
Have a good one.
List out all of the factors to 32.
1, 2, 4, 8, 16, 32
From the list, we either have 4 or 16 as our number.
Prime factorisation for 4 is 2 x 2 and prime factorisation for 16 is 2 x 2 x 2 x 2
Thus, that doesn't help our case.
Looking at our requirement: the sum of its digits is odd.
Well, 4 can be rewritten as 0 4 and its sum is even.
The sum for 1 + 6 is obviously odd, which means that 16 is the number.
Answer:
Solve v + 6 = 5v − 2 to find the value of v.
Step-by-step explanation:
