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3 years ago

How are these triangles similar

Mathematics

2 answers:

o-na [289]3 years ago

8 0

Yeah they both are right angle triangles and they have similar size acute angles too

MAXImum [283]3 years ago

6 0

Answer:

they both have right angles

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Which ratios are equivalent to the given ratio?

Alex73 [517]

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3 years ago

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How many students participate in extracurricular activities?

VikaD [51]

Answer:

527 students

Step-by-step explanation:

you convert the percent by moving the decimal point two places to the left making it 0.62 then you multiply it by 850 which gets you 527.

aka

850 x 0.62 = 527

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3 years ago

How would I solve <img src="https://tex.z-dn.net/?f=8%5E%7B3%2F2%7D%20%2A%202%5E%7B3%2F2%7D" id="TexFormula1" title="8^{3/2} * 2

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The asnwer is 36 i think

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3 years ago

Trent has some yellow, red, green, and blue cubes. Exactly 1/5 of the cubes are yellow and 1/6 of the cubes are green. Which of

Alika [10]

Answer:

Trent has at least 30 cubes.

Step-by-step explanation:

This is because the lowest common multiple of both 5 and 6 is 30. In order for you to get fractions with those denominators, there would have to be a total number in which they share the multiple.

8 0

4 years ago

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The table shows the results of a survey in which 10th-grade students were asked how many siblings (brothers and/or sisters) they

lesantik [10]

Answer:

70%

Step-by-step explanation:

Given

Number of Siblings: || 0 || 1 || 2 || 3

Number of Students: || 4 || 18 || 10 || 8

Required

Determine the probability of a student having at least one but not more than 2 siblings

First, we have to determine the total number of 10th grade students

$Total = 4 + 18 + 10 + 8$

$Total = 40$

The probability of a student having at least one but not more than 2 siblings = P(1) + P(2)

Solving for P(1)

P(1) = number of students with 1 sibling / total number of students

From the given parameters, we have that:

Number of students with 1 sibling = 18

So:

$P(1) = \frac{18}{40}$

Solving for P(2)

P(2) = number of students with 2 siblings / total number of students

From the given parameters, we have that:

Number of students with 2 siblings = 10

So:

$P(2) = \frac{10}{40}$

$P(1) + P(2) = \frac{18}{40} + \frac{10}{40}$

Take LCM

$P(1) + P(2) = \frac{18 + 10}{40}$

$P(1) + P(2) = \frac{28}{40}$

Divide numerator and denominator by 4

$P(1) + P(2) = \frac{7}{10}$

$P(1) + P(2) = 0.7$

Convert to percentage

$P(1) + P(2) = 70\%$

Hence, the required probability is 70%

6 0

3 years ago