Answer:
- $8000 at 1%
- $2000 at 10%
Step-by-step explanation:
It often works well to let a variable represent the amount invested at the higher rate. Then an equation can be written relating amounts invested to the total interest earned.
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<h3>setup</h3>
Let x represent the amount invested at 10%. Then 10000-x is the amount invested at 1%. The total interest earned is ...
0.10x +0.01(10000 -x) = 280
<h3>solution</h3>
Simplifying gives ...
0.09x +100 = 280
0.09x = 180 . . . . . . . subtract 100
x = 2000 . . . . . . divide by 0.09
10000 -x = 8000 . . . . amount invested at 1%
<h3>1.</h3>
$8000 should be invested in the 1% account
<h3>2.</h3>
$2000 should be invested in the 10% account
Answer: (1,50) (2,100) (3,150) (4,200) (5,250) (6,300) (7,350) (8,400) (9,450)
Step-by-step explanation:
Answer:
y = -6/5x+56/5
Step-by-step explanation:
Answer:
()***********************
<--------------------(-2)-------(0)------(2)--------------------------->
Step-by-step explanation:
Subtract 
on both sides:
Simplify both sides:
Divide both sides by 2:
So this means we want values of greater than 2, not including 2.
()***********************
<--------------------(-2)-------(0)------(2)--------------------------->
