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Alika [10]
3 years ago
14

15+15+15=45 7+7+7=21 4+4+4=12 4+15×7=?​

Mathematics
1 answer:
vesna_86 [32]3 years ago
3 0

Answer:

109

Step-by-step explanation:

15+15+15= 45

7+7+7=21

4+4+4=12

4+15×7=109

I hope this helps!

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A garden hose having an internal diameter of 0.740 in. ( 1.8796 cm ) is connected to a lawn sprinkler that consists merely of an
lara31 [8.8K]

Answer:

It will leave the sprinkler at speed of v_2=613.87m/sec

Step-by-step explanation:

We have given internal diameter of the garden hose d_1=0.740in=1.8796cm

So radius r_1=\frac{d_1}{2}=\frac{1.8796}{2}=0.9398cm

So area A_1=\pi r_1^2=3.14\times 0.9398^2=2.7733cm^2

Water in the hose has a speed of 4 ft/sec

So v_1=4ft/sec=121.92cm/sec(As\ 1ft/sec\ =30.48cm/sec)

Number of holes n = 36

Diameter of each hole d_2=0.1397cm

So radius r_2=0.0698cm

So area A_2=\pi r^2=3.14\times 0.0698^2=0.0153cm^2

From continuity equation

A_1v_1=nA_2v_2

2.7733\times 121.92=36\times 0.0153\times v_2

v_2=613.87m/sec

7 0
3 years ago
What is equivalent to 4/9(2n-3)
sp2606 [1]
4/9(2n)+4/9(-3)
(4x2/9)n+(4 x -3)/9
(8/9)n -12/9
8/9n-4/3
4 0
3 years ago
Lcm of (x-2)(x+3) and 10(x+3)^2
Arte-miy333 [17]
Least common multiple: factor them, then see what they have in common and what is leftover and multiply those expressions:

(x - 2)(x + 3)          10(x + 3)(x + 3)
Common: (x + 3)
Leftover: (x - 2), (10), (x + 3)
Common · Leftover is: (x + 3) · (x - 2) · (10) · (x + 3) = 10(x - 2)(x + 3)²

Answer: LCM is 10(x - 2)(x + 3)²


8 0
3 years ago
A textile mill wishes to establish a control procedure on flaws in towels it manufactures. Using an inspection unit of 50 units,
Natasha_Volkova [10]

Answer:

•A c-chart is the appropriate control chart

• c' = 8.5

• Control limits, CL = 8.5

Lower control limits, LCL = 0

Upper control limits, UCL = 17.25

Step-by-step explanation:

A c chart is a quality control chart used for the number of flaws per unit.

Given:

Past inspection data:

Number of units= 100

Total flaws = 850

We now have:

c' = 850/100

= 8.5

Where CL = c' = 8.5

For control limits, we have:

CL = c'

UCL = c' + 3√c'

LCL = c' - 3√c'

The CL stands for the normal control limit, while the UCL and LCL are the upper and lower control limits respectively

Calculating the various control limits we have:

CL = c'

CL = 8.5

UCL = 8.5 + 3√8.5

= 17.25

LCL = 8.5 - 3√8.5

= -0.25

A negative LCL tend to be 0. Therefore,

LCL = 0

4 0
3 years ago
It cost Jocelyn $5.60 to send 56 text messages. How much would it cost to send 198
victus00 [196]

Answer:

$19.8

Step-by-step explanation:

To find the answer, find the  ratio.

7 0
3 years ago
Read 2 more answers
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