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Nastasia [14]
3 years ago
10

If m/n = 3, what does 2n/m equal?

Mathematics
2 answers:
IceJOKER [234]3 years ago
7 0

Answer:

That would be n\geq 1\\

Step-by-step explanation:

Rufina [12.5K]3 years ago
5 0

(Hard) A composite number n is called a Carmichael number bn−1 ≡ 1 (mod n) for every number b such ... Base case: When n = 2 the formula a + c ≡ b + d (mod m) was already given. ... The sequence goes 1, 3, 7, 15, 31,... guess that it is equal to 2n+1 − 1. ... Prove (now using induction on n) that fm|fmn for all n ≥ 1.

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Factorization 36+121c2+132c
Sliva [168]

Answer:

(6+11c)^2

hope this helps :)

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3 years ago
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A smaller square is located inside a larger square. the length of the smaller square is 7 cm, and the length of the square is 12
patriot [66]
Let S=larger square side and s=smaller square side.  The area between the larger and smaller is simple the larger area minus the smaller area.  The area of any square being s^2.  So our remaining area is:

A=S^2-s^2

A=144-49=95 cm^2
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3 years ago
A shoreline is eroding at a rate of 1/3 3 foot per 3 months. How many feet are eroding per year?
salantis [7]
7ft if 3+1/3 hopefully this helps i did hwat i can










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3 years ago
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The table shows the location of four cites relative to sea level. Find the city that is closest to sea level.
STatiana [176]
The answer is C.
Because it is closest location relative to the sea!
4 0
3 years ago
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Find the value of x in each case: Given: Iso. ΔABC, HM ∥DG Find: x, m∠CAB, m∠CBA
AleksAgata [21]

1. Start with ΔCIJ.

  • ∠HIC and ∠CIJ are supplementary, then m∠CIJ=180°-7x;
  • the sum of the measures of all interior angles in ΔCIJ is 180°, then m∠CJI=180°-m∠JCI-m∠CIJ=180°-25°-(180°-7x)=7x-25°;
  • ∠CJI and ∠KJA are congruent as vertical angles, then m∠KJA =m∠CJI=7x-25°.

2. Lines HM and DG are parallel, then ∠KJA and ∠JAB are consecutive interior angles, then m∠KJA+m∠JAB=180°. So

m∠JAB=180°-m∠KJA=180°-(7x-25°)=205°-7x.

3. Consider ΔCKL.

  • ∠LFG and ∠CLM are corresponding angles, then m∠LFG=m∠CLM=8x;
  • ∠CLM and ∠CLK are supplementary, then m∠CLM+m∠CLK=180°, m∠CLK=180°-8x;
  • the sum of the measures of all interior angles in ΔCLK is 180°, then m∠CKL=180°-m∠CLK-m∠LCK=180°-(180°-8x)-42°=8x-42°;
  • ∠CKL and ∠JKB are congruent as vertical angles, then m∠JKB =m∠CKL=8x-42°.

4. Lines HM and DG are parallel, then ∠JKB and ∠KBA are consecutive interior angles, then m∠JKB+m∠KBA=180°. So

m∠KBA=180°-m∠JKB=180°-(8x-42°)=222°-8x.

5. ΔABC is isosceles, then angles adjacent to the base are congruent:

m∠KBA=m∠JAB → 222°-8x=205°-7x,

7x-8x=205°-222°,

-x=-17°,

x=17°.

Then m∠CAB=m∠CBA=205°-7x=86°.

Answer: 86°.

3 0
3 years ago
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