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prohojiy [21]
3 years ago
7

Which linear inequality is represented by the graph?

Mathematics
2 answers:
brilliants [131]3 years ago
5 0

Answer:

The linear inequality would be y ≥ 1/2x - 1

Step-by-step explanation:

In order to find the inequality, first find the equation of the line. To do this, we start by identifying two points on the line. For the purpose of this, we'll use (0, -1) and (2, 0). Now we can use the slope formula to find the slope.

m(slope) = (y2 - y1)/(x2 - x1)

m = (0 - -1)/(2 - 0)

m = 1/2

Now that you have the slope, you can use either point and point-slope formula.

y - y1 = m(x - x1)

y - 0 = 1/2(x - 2)

y = 1/2x - 1

Now that we have this, we look to the shading. If the shading is above, then we make y ≥. If it is under the line, then we make y ≤. In this case, the shading is above. Leaving us with:

y ≥ 1/2x - 1

miskamm [114]3 years ago
3 0

Answer:

y\geq\dfrac{1}{3}x-1

Step-by-step explanation:

Given: The graph of inequality.

First choose two points on graph and find the equation of line.

From graph two passing points are (3,0) and (0,-1)

using two point formula of line to find the equation.

y-(-1)=\dfrac{0+1}{3-0}(x-0)

y+1=\dfrac{1}{3}x

y=\dfrac{1}{3}x-1

Now we find inequality.

Line is solid on graph. Equality would be there.

point (0,0) is part of shaded region.

(0,0) must be true for above equation.

Check the points

0 \text{___} \dfrac{1}{3}(0)-1

0 \text{___} -1

As we know 0 is greater than -1.

Hence, The equation of inequality y\geq\dfrac{1}{3}x-1

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Answer:

x < 6

Step-by-step explanation:

x/-1 > -6

x < (-6) * (-1)

so, x < 6

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Let f be the function defined as follows:1. If a = 2 and b = 3, is f continuous at x = 1? Justify your answer.2. Find a relation
Arada [10]

Answer:

1. not continuous, as the function definitions deliver different function values at x=1 when approaching this x from the left and from the right side.

2.

2 = a + b

3.

0 = 2a + b

4.

a = -2

b = 4

Step-by-step explanation:

the function is continuous at a specific point or value of x, if the f(x) = y functional value is the same coming from the left and the right side at that point.

1. that means that for x=1

3 - x = ax² + bx

so,

3 - 1 = a×1² + b×1 = a + b

2 = a + b

we have to use a=2 and b=3

2 = 2 + 3 = 5

2 is not equal 5, so the assumed equality is false, so the function is not continuous there.

2. point 1 gave us already the working relationship between a and b.

2 = a + b

only if that is true, is the function continuous at x=1.

3. now for x=2

5x - 10 = ax² + bx

5×2 - 10 = a×2² + b×2 = 4a + 2b

10 - 10 = 4a + 2b

0 = 4a + 2b

0 = 2a + b

4. to find a and b to be continuous at both locations x=1 and x=2 both expressions in a and b must apply.

so, they establish a system of 2 equations with 2 variables.

2 = a + b

0 = 2a + b

a = 2 - b

0 = 2×(2-b) + b = 4 - 2b + b = 4 - b

b = 4

therefore

a = 2 - 4 = -2

5. I cannot draw a graph here.

just use now the function

3 - x, x < 1

‐2x² +4x, 1 <= x < 2

5x - 10, x >= 2

8 0
3 years ago
Which best describes how to solve the equation below 26x=74
djyliett [7]
X=74/26
x=37/13
Remember give me a heart<3
6 0
3 years ago
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