Answer:
y
=
74.08
Step-by-step explanation:
Answer:
15
Step-by-step explanation:
brainliest plzzz
Answer:
C = 75 in
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
Assume that the height of all people follows a normal distribution with a mean of 69 in and a standard deviation of 2.9 in.
This means that ![\mu = 69, \sigma = 2.9](https://tex.z-dn.net/?f=%5Cmu%20%3D%2069%2C%20%5Csigma%20%3D%202.9)
Calculate the cut-off height (C) that ensures only people within the top 2.5% height bracket are allowed into the team.
This is the 100 - 2.5 = 97.5th percentile, which is X when Z has a pvalue of 0.975, so X when Z = 1.96.
![Z = \frac{X - \mu}{\sigma}](https://tex.z-dn.net/?f=Z%20%3D%20%5Cfrac%7BX%20-%20%5Cmu%7D%7B%5Csigma%7D)
![1.96 = \frac{X - 69}{2.9}](https://tex.z-dn.net/?f=1.96%20%3D%20%5Cfrac%7BX%20-%2069%7D%7B2.9%7D)
![X - 69 = 1.96*2.9](https://tex.z-dn.net/?f=X%20-%2069%20%3D%201.96%2A2.9)
![X = 74.7](https://tex.z-dn.net/?f=X%20%3D%2074.7)
Rounded to the nearest inch,
C = 75 in
Answer:
20
Step-by-step explanation:
( x − 2 ) 2 − 16 Set y equal to the new right side. y = ( x − 2 ) 2 − 16 Use the vertex form, y = a ( x − h ) 2 + k , to determine the values of a , h , and k . a = 1 h = 2 k = − 16 Find the vertex ( h , k ) . ( 2 , − 16 )
Answer:
Step-by-step explanation:
<u>Dimensions of the picture:</u>
<u>Area of the picture:</u>
Scale factor = 2.5
<u>Enlarged picture's area:</u>
- 40*2.5*2.5 = 250 in² (scale factor affects both dimensions)
Option B is correct