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enyata [817]
3 years ago
11

Please fill in the blanks for problem #10

Mathematics
1 answer:
Ugo [173]3 years ago
7 0

Answer:

1) $55

2) less than

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I need help with this question please.
vredina [299]

Answer:

tan(2x)=-24/7

Step-by-step explanation:

Since tan(x)=sin(x)/cos(x)

We are going to need sin(x) any time, so lets find it right away.

To do this, remember that. sin(x)^2 + cos(x)^2=1

so. sin(x)= \sqrt{1 - (cos(x)^{2} )}=\sqrt{1-(-4/5)^{2} }

This leads to.

\sqrt{\frac{25-16}{25} } =\sqrt{\frac{9}{25} }=+/- 3-5

We have obtained two solutions, -3/5 and 3/5.

We need to pick one, since not all of them are correct for our scenario, in this case, we've been told that x belongs to the range [180, 270], in this range, sin(x)<0.

So in our previous solution, we have that sin(x)= -3/5

Now, to find tang(2x), we need to apply the definition

Tang(2x)=sin(2x)/cos(2x).

Lets remember that

sin(2x)=2*sin(x)*cos(x)

cos(2x)=cos(x)^2 - sin(x)^2.

Lets evaluate our given result.

sin(2x)=2*(-3/5)*(4/5)=-24/25

cos(2x)=(-4/5)^2 - (3/5)^2=7/25

Hence

tan(2x)= -(24/25) / (7/25)=-24/7

5 0
3 years ago
How can polygons be considered a subcategory of two-dimensional figures?
Sonbull [250]
I say subcategory would be a good answer
6 0
3 years ago
PLS HELP.
frozen [14]

Answer:

15 people

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The Weibull distribution is widely used in statistical problems relating to aging of solid insulating materials subjected to agi
fenix001 [56]

Answer:

Step-by-step explanation:

Given that

\alpha =2.5 ,\beta =220

The weibull distribution with parameters \alpha \ \ and \ \ \beta

where \alpha =0 \ \ , \beta =0

F(x,\alpha ,\beta) \left|\begin{array}{cc}\frac{\alpha }{\beta } x^{\alpha-1e^-(x/\beta)^\alpha  &x\geq 0\\0&x

Then,

F(x,\alpha ,\beta )=\left|\begin{array}{cc}0&x

A) The probability that a specimen's lifetime is at most 250 is

P(X\leq 250)=F(250,2.7,220)\\\\=1-e^-^(250/220)^{2.7}\\\\=1-0.2436\\\\=0.7564

The probability that the specimen's life time is more than 300 is

P(X>300)=1-P(X\leq 300)\\\\=1-F(300;2.7,220)\\\\=1-(1-e^-^{(300/220)^{2.7}

=e^-^{(300/220)^{2.7}

= 0.0992

b)The probability of the specimen's lifetime is between 100 and 250

P(100

c) The value such that exactly 50% of all specimens have lifetimes exceeding that value is

P(X>x)=0.50\\\\1-P(X

x = 192.07

7 0
3 years ago
Question 1 (1 point)
Elena L [17]
Its a translation otherwise known as a slide
5 0
2 years ago
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