Answer:
(2, 1)
Step-by-step explanation:
The best way to do this to avoid tedious fractions is to use the addition method (sometimes called the elimination method). We will work to eliminate one of the variables. Since the y values are smaller, let's work to get rid of those. That means we have to have a positive and a negative of the same number so they cancel each other out. We have a 2y and a 3y. The LCM of those numbers is 6, so we will multiply the first equation by a 3 and the second one by a 2. BUT they have to cancel out, so one of those multipliers will have to be negative. I made the 2 negative. Multiplying in the 3 and the -2:
3(-9x + 2y = -16)--> -27x + 6y = -48
-2(19x + 3y = 41)--> -38x - 6y = -82
Now you can see that the 6y and the -6y cancel each other out, leaving us to do the addition of what's left:
-65x = -130 so
x = 2
Now we will go back to either one of the original equations and sub in a 2 for x to solve for y:
19(2) + 3y = 41 so
38 + 3y = 41 and
3y = 3. Therefore,
y = 1
The solution set then is (2, 1)
Exponent rules : (a^m)^n = a^(mn) and a^0 = 1
(4^9)^5 * 4^0 =
4^45 * 1 =
4^45 <==
Answer:
sec (x)
Step-by-step explanation:
sec (x) tan (x) cos (x) csc (x) =
We know sec = 1/ cos
Tan = sin/cos
csc = 1/sin
Replacing into the expression
1/ cos (x) * sin(x)/ cos (x) * cos (x) * 1 / sin(x)
Canceling like terms
1/ cos (x)
sec(x)
Answer:
That something unexpected is about to happen.
Step-by-step explanation:
For this case we have an exponential expression of the form:
We can rewrite the exponential expression using power properties.
We have then:
From here, we take the square root of 36.
We have then:
Answer:
The exponential function is given by:
