Answer:
60 minutes for the larger hose to fill the swimming pool by itself
Step-by-step explanation:
It is given that,
Working together, it takes two different sized hoses 20 minutes to fill a small swimming pool.
takes 30 minutes for the larger hose to fill the swimming pool by itself
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
<u>To find LCM of 20 and 30</u>
LCM (20, 30) = 60
<u>To find the efficiency </u>
Let x be the efficiency to fill the swimming pool by larger hose
and y be the efficiency to fill the swimming pool by larger hose
x = 60/30 =2
x + y = 60 /20 = 3
Therefore efficiency of y = (x + y) - x =3 - 2 = 1
so, time taken to fill the swimming pool by small hose = 60/1 = 60 minutes
Answer: x ≤ 10
Step-by-step explanation:
20 + 13x ≤ 150
13x ≤ 150 - 20
13x ≤ 130
x ≤ 130 ÷ 13
x ≤ 10
Answer:
D) 5/2 divided by 8/6
Step-by-step explanation:
Let's say is "x", so, then "x" is the 100%, and we know that the 60% is 120, what the dickens is "x" anyway?
Answer:
2x-3y=-15
Step-by-step explanation:
y=2/3x+5 and write in standard form.
and you come up with 2x-3y=-15.
