Answer:
No. pp you can fit in a van: 6,
No. pp you can fit in a bus: 20
Step-by-step explanation:
Let v = # of pp in vans, and let b = # of pp in buses:
8v + 9b = 228,
4v + 5b = 124
If we solve this system of equations by substitution, we isolate the first eq. for v and then substitute into the bottom eq:
v = 228-9b/8,
Substitute v = 228-9b/8 into bottom eq:
[4 * 228-9b/8 + 5b = 125]
[228+b/2=124]
[228+b = 248]
[b = 20]
Now substitute 20 to find no. of pp in the vans:
v = 228 - 9(20)/8 = 228 - 180/8 = 48/8 = 6
L = 3 + 2w
Find the width
Area = 54
l × w = 54
(3 + 2w) × w = 54
3w + 2w^2 = 54
2w^2 + 3w - 54 = 0
(2w - 9)(w + 6) = 0
w = 9/2 or w = -6 (width shouldn't be negative)
w = 9/2
w = 4.5 m
Find the length
l = 3 + 2w
l = 3 + 2(4.5)
l = 3 + 9
l = 12 m
The width is 4.5 m, the length is 12 m
Answer: 58 14ths
Step-by-step explanation:
multiply 14 by 4 to get 56 14ths, then add the 2
The midpoint bisects PR, making it 2 equal halves.
Answer:
A. Infinitely many solutions.
Step-by-step explanation:
The row and column numbers are equal in the echelon. This rows have 0001 numbers which indicates that there is free variable at the end. The reduced row echelon has equal number of rows and columns. There are infinitely many solution as the numbers in the rows are zero ending of the free variable 1. If there is no free variable then there will be no solution.
