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Sedaia [141]
3 years ago
14

Which situations can be presented by an exponential function?

Mathematics
2 answers:
Zanzabum3 years ago
5 0

Answer:

c and d

Step-by-step explanation:

i just took the test

Evgesh-ka [11]3 years ago
3 0

Answer:

It’s C and D I just finished the text and finished with 100% thanks to the person in the comments in the question below

Step-by-step explanation:

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What is the value of x?
allsm [11]
First need to find the length of line LJ

Line LJ = 8sqrt2 * sin(30) = 5.6569

 now use that to find x

x = 5.6569 * sin(45) = 4

6 0
3 years ago
Is 5/4 greater then 1
zalisa [80]

Answer:

Yes

Step-by-step explanation:

5/4 = 1 1/4 or 1.25 and that I'd greater than 1

3 0
4 years ago
In the figure below, \overline{AD} AD start overline, A, D, end overline and \overline{BE} BE start overline, B, E, end overline
VLD [36.1K]

Answer:

<u>The measure of the arc CD = 64°</u>

Step-by-step explanation:

It is required to find the measure of the arc CD in degrees.

So, as shown at the graph

BE and AD are are diameters of circle P

And ∠APE is a right angle ⇒ ∠APE = 90°

So, BE⊥AD

And so, ∠BPE = 90° ⇒(1)

But it is given: ∠BPE = (33k-9)° ⇒(2)

From (1) and (2)

∴ 33k - 9 = 90

∴ 33k = 90 + 9 = 99

∴ k = 99/33 = 3

The measure of the arc CD = ∠CPD = 20k + 4

By substitution with k

<u>∴ The measure of the arc CD = 20*3 + 4 = 60 + 4 = 64°</u>

6 0
3 years ago
What is StartFraction 7 Over 9 EndFraction divided by one-third?
nordsb [41]

Answer:

D, two and one third

Step-by-step explanation:

i used a calculator

6 0
3 years ago
Read 2 more answers
Find the value of the combination. From a committee consisting of 8 men and 5 women, a subcommittee is formed consisting of 4 me
Alex787 [66]

Out of 8 men, 4 can be selected and lined up in (8 x 7 x 6 x 5) = 1,680 ways.
But within that number, each group of 4 appears in (4 x 3 x 2) = 24 orders.
So there are (1,680 / 24) = 70 different groups of men.

Out of 5 women, 3 can be selected and lined up in (5 x 4 x 3) = 60 ways.
But within that number, each group of 3 appears in (3 x 2) = 6 orders.
So there are (60 / 6) = 10 different groups of women.

Each different group of 70 men can be joined by any of the 10 groups
of women. So the total number of possible subcommittees is (70 x 10) = 700 . 

5 0
3 years ago
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