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Andru [333]
3 years ago
7

Simplify tan9x-tan5x / 1+tan9xtan5x​

Mathematics
1 answer:
Wittaler [7]3 years ago
5 0

Answer:

The given expressions simplifies to tan (4x).

Step-by-step explanation:

Here, the given expression is : \frac{tan9x - tan5x}{1+ tan9xtan5x}

By TRIGONOMETRIC IDENTITY:

tan (A-B)  = \frac{tanA - tanB}{1+ tanAtanB}

Putting this identity here, and taking A = 9 x, B = 5 x, we get

\frac{tan9x - tan5x}{1+ tan9xtan5x} = tan (9x-5x)

= tan(4x)

Hence, the given expressions simplifies to tan (4x).

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Joey makes 20 less dollars than Jeremy. If they make a total of $72, how much does
svetoff [14.1K]

Answer:

Joey makes 52 dollars

Step-by-step explanation:

7 0
3 years ago
Se quiere construir un muro de 4 m de alto, 12 m de largo y 10 cm de espesor. ¿Cuántos ladrillos de 8 cm de alto, 20 cm de largo
Llana [10]

Answer:

3000

Step-by-step explanation:

Let's start by finding the volume of the wall. The volumen of the wall can be considered as the volume of a rectangular prism. The volume of a rectangular prism is given by:

V_w=w*l*h\\\\Where:\\\\w=Width=10cm=0.1m\\l=Length=12m\\h=Height=4m

So the volume of the wall is:

V_w=0.1*12*4=4.8m^3

Now, we can find the volume of the brick using the same method since a brick can be considered as a rectangular prism as well:

V_b=w*l*h\\\\For\hspace{3}the\hspace{3}brick\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m

Hence:

V_b=(0.1)*(0.2)*(0.08)=0.0016m^3

In order to know how many bricks are required to build the wall, we just need to fill the wall volume with the number of bricks of this volume. So:

V_w=nV_b\\\\Where\\\\n=Number\hspace{3}of\hspace{3}bricks

Solving for n:

n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000

Therefore, we need 3000 bricks to build that wall.

Translation:

Comencemos por encontrar el volumen del muro. El volumen del muro puede considerarse como el volumen de un prisma rectangular. El volumen de un prisma rectangular viene dado por:

V_w=w*l*h\\\\Donde:\\\\w=Espesor=10cm=0.1m\\l=Largo=12m\\h=Alto=4m

Entonces el volumen del muro es:

V_w=0.1*12*4=4.8m^3

Ahora, podemos encontrar el volumen del ladrillo utilizando el mismo método, ya que un ladrillo también puede considerarse como un prisma rectangular:

V_b=w*l*h\\\\Para\hspace{3}el\hspace{3}ladrillo\\\\w=10cm=0.1m\\l=20cm=0.2m\\h=8cm=0.08m

Por lo tanto:

V_b=(0.1)*(0.2)*(0.08)=0.0016m^3

Para saber cuántos ladrillos se requieren para construir el muro, solo necesitamos llenar el volumen del muro con la cantidad de ladrillos de este volumen. Entonces:

V_w=nV_b\\\\Donde\\\\n=Numero\hspace{3}de\hspace{3}ladrillos

Resolviendo para n:

n=\frac{V_w}{V_b} =\frac{4.8}{0.0016} =3000

Por lo tanto, necesitamos 3000 ladrillos para construir ese muro.

4 0
4 years ago
When solving the equation x2 – 8x - 7 = 0 by completing the square, which equation
IgorLugansk [536]
<h3><u>A</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u><u>:</u><u>-</u></h3>

Lets Solve

\\  \rm \longmapsto \:  {x}^{2}  - 8x - 7 = 0 \\  \\  \rm \longmapsto \:  {x}^{2}  - 8 {}^{}x = 7 \\  \\  \rm \longmapsto \: 4( {x}^{2}  - 8x) = 4 \times 7 \\  \\  \rm \longmapsto \:  {4x}^{2}  - 32x = 28 \\  \\  \rm \longmapsto \:  {(2x)}^{2}  - 2 \times 2x \times 8 = 28 \\  \\  \rm \longmapsto \: (2x) {}^{2}  - 2 \times 2x \times 8 +  {8}^{2}  = 28 +  {8}^{2}  \\  \\  \rm \longmapsto \:  {(2x - 8)}^{2}  = 64 + 28 \\  \\  \rm \longmapsto \:  {(2x - 8)}^{2}  = 92 \\  \\  \rm \longmapsto \: 2x - 8 =  \underline{ + }9.3 \\ \\  \rm \longmapsto \:2x =  8 + 9.3  \: or \: 8 - 9.3 \\ \\  \rm \longmapsto \:2x = 17.3 \:or \:  - 1.3 \\ \\  \rm \longmapsto \:2x = 17.3 \\ \\  \rm \longmapsto \:x =  \frac{17.3}{2}  \\ \\  \rm \longmapsto x = \:8.6

  • Ignore negative value
4 0
3 years ago
Which equation is parrel to the equation y=3x-4​<br>y=3x-8<br>y=4x+2<br>y=x-9<br>y=-1/3x+4
slega [8]

Answer:

Parallel means they have the same slope so, y=3x-8

4 0
3 years ago
(fg)-1(5)=g-1f-1(5)​
larisa86 [58]

Answer:

<em>f = g/ g+1</em>

Step-by-step explanation:

Remove Parenthesis.

<em>fg - 1  x 5  = g  - 1  x f  - 1 x 5</em>

Cancel <em>-1 x 5</em> on both sides.

<em>fg =  g - 1  x f</em>

Simplify <em>1 x f</em>  to f.

<em>fg =  g - f</em>

Add <em>f </em>to both sides.

<em>fg + f = g</em>

Factor out the common term <em>f.</em>

<em>f (g + 1)  = g</em>

Divide both sides by <em>g + 1</em>

<em>f =  g/ g + 1</em>

6 0
4 years ago
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