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zhuklara [117]
3 years ago
8

Omar can buy at most 8 pairs of socks​

Mathematics
1 answer:
kondor19780726 [428]3 years ago
4 0
Where’s the rest of the question?
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My cousin borrowed $18,000 for a new car loan for 6 years. He told me that at the end of the loan, he had paid $25,560 for the i
scZoUnD [109]

Answer:

A

Step-by-step explanation:

3 0
3 years ago
There are 12 students in a classroom, including the triplets joey, chloe, and zoe. If 3 of the 12 are randomly selcted to give s
forsale [732]

The probability of choosing Joey first is  1/12 .

If that happens, the probability of choosing Chloe next is  1/11 .

Then, the probability of choosing Zoe after that is  1/10 .

The probability of all these things happening is

          (1/12) x (1/11) x (1/10) 

       =  1/1320 = 0.00076 = 0.076 percent 

3 0
3 years ago
If g(x) = x+1/ x-2 and h (x) =4 - x , what is the value of ( g*h) (-3)?
Lapatulllka [165]

<u>Answer:</u>

g (h (x) ) = 5/8

<u>Step-by-step explanation:</u>

We are given the following two functions and we are to find the value of g ( h ( - 3 ) ):

g ( x ) = \frac { x + 1 } { x + 2 }

h ( x ) = 4 - x

Firstly, we need to find the function :

g ( h ( x ) ) = \frac { ( 4 - x + 1 ) } { ( 4 - x - 2 ) } = \frac { 5 - x } { 2 - x }

Now substituting the value x=-3 in it:

g ( h ( x ) ) = \frac { 5 - (-3) } { 2 - (-3) }

g (h (x) ) = 5/8

5 0
2 years ago
PLEASE HELP ME ASAP! Are my answers correct?
likoan [24]
Yes, they are correct
4 0
2 years ago
Read 2 more answers
99 POINTS, NEED HELP WITH ALGEBRA
Tanya [424]

1 is in picture above.

2.

average \: rate =  \frac{f(4) - f(1)}{4 - ( - 1)}  =  \frac{5}{4 - ( - 1)}  = 1

3. In the picture...

4. In the picture...

5. Parts A and B are true.

6.

average \: rate =  \frac{f(0) - f( - 10)}{0 - ( - 10)}  =  \frac{( - 6) -  184}{0 - ( - 10)}  =  \frac{ - 190}{10}  =  - 19

7. The axis symmetry equation of

y = a {x}^{2}  + bx + c

is

x =  \frac{ - b}{2a}

So it would be x=-3/4

8.

y =  {(x - 6)}^{2}  + 10

T=(6, 10) vertex coordinates...

4 0
3 years ago
Read 2 more answers
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