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3 years ago

It has to do with slopes or something

Mathematics

1 answer:

Ostrovityanka [42]3 years ago

4 0

What is it that I am supposed to be doing?

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Convert each of the following estimates of useful life to a straight-line depreciation rate, stated as a percentage: (a) 10 year

Rzqust [24]

Answer:

a.10 years 1 / 10 x 100 10% per year

b. 8 years 1 / 8 x 100 12.5% per year

c. 25 years 1 / 25 x 100 4% per year

d. 40 years 1 / 40 x 100 2.5% per year

e. 5 years 1 / 5 x 100 20% per year

f. 4 years 1 / 4 x 100 25% per year

g. 20 years 1 / 20 x 100 5% per year

Step-by-step explanation:

Under straight line method of depreciation, equal amount of the depreciation is reduced throughout the useful life of the asset. Using the following formula:

<u>Straight line depreciation rate = 1 / Useful Life x 100 </u>

So:

a.10 years 1 / 10 x 100 10% per year

b. 8 years 1 / 8 x 100 12.5% per year

c. 25 years 1 / 25 x 100 4% per year

d. 40 years 1 / 40 x 100 2.5% per year

e. 5 years 1 / 5 x 100 20% per year

f. 4 years 1 / 4 x 100 25% per year

g. 20 years 1 / 20 x 100 5% per year

7 0

3 years ago

Please help with geometry homework ! Mark brainliest

TiliK225 [7]

Theorem: If two chords intersect within a circle, then the product of the lengths of the segments (parts) of one chord is equal to the product of the lengths of the segments of the other chord.

In oyur case,

$2\cdot x=3\cdot 4.$

Solve this equation to find x:

$x=\dfrac{3\cdot 4}{2}=6.$

Answer: 6, choice B.

7 0

3 years ago

Which measurement is closest to the area of the border, or the shaded region of this figure in square inches?

Arada [10]

Answer:

GGGGGGGGGGGGGGGGGGGGG

7 0

3 years ago

Find an equation for the plane that is tangent to the surface z equals ln (x plus y )at the point Upper P (1 comma 0 comma 0 ).

alexira [117]

Let $f(x,y,z)=z-\ln(x+y)$ . The gradient of $f$ at the point (1, 0, 0) is the normal vector to the surface, which is also orthogonal to the tangent plane at this point.

So the tangent plane has equation

$\nabla f(1,0,0)\cdot(x-1,y,z)=0$

Compute the gradient:

$\nabla f(x,y,z)=\left(\dfrac{\partial f}{\partial x},\dfrac{\partial f}{\partial y},\dfrac{\partial f}{\partial z}\right)=\left(-\dfrac1{x+y},-\dfrac1{x+y},1\right)$