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3 years ago

Match the inequality with its line graph.

Mathematics

1 answer:

zepelin [54]3 years ago

8 0

Answer:

The answer to your question is below

Step-by-step explanation:

A) 2x > -6

x > -6/2

x > -3

It must be a graph with an open circle starting at -3 and then to the right.

It is the first graph.

B) x - 4 < -7

x < -7 + 4

x < -3

The graph must be an open circle starting at -3 and pointing to the left.

it is the second graph.

C) 6 + x ≤ 3

x ≤ -6 + 3

x ≤ -3

The graph must be a closed circle starting at -3 and pointing to the left.

it is the forth graph.

D) -x - 5 ≤ -2

-x ≤ -2 + 5

- x ≤ 3

x ≥ -3

The graph must be a closed circle starting at -3 and pointing to the right.

It is the third graph.

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Answer:

y=3/4x+2 is the answer

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3 years ago

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Yuki888 [10]

Answer:

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Step-by-step explanation:

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3 years ago

What is a true statement about negative exponents?

Nadya [2.5K]

Answer:

Raising something to a negative exponent is just taking the reciprocal of the amount.

Step-by-step explanation:

Let's assume that you wanted to know what $x^{-2}$ is.

To find it, you would take the reciprocal of the x amount. So $x^{-2}$ becomes $\frac{1}{x^{2}}$ .

This works because of the nature of exponents. Exponents represent the number of times you are multiplying a value by itself. So $a^{3}$ would be equal to a · a · a. To increase the exponent, you increase the number of times the value is multiplied by itself: To increase $a^{3}$ to $a^{5}$ , you would have to multiply a with $a^{3}$ two more times (a · a · a · a · a). To decrease the exponent, you must divide the value by itself. So to decrease $a^{5}$ to $a^{2}$ , you would have to divide $a^{5}$ by a 3 times.

If the exponent is 0, the value is equal to 1. But you can still decrease the exponent into negative numbers. You just divide 1 by a the desired amount of times: $\frac{1}{a^{3}}$ means that you are dividing 1 by a 3 times.

Hope this helps.

3 0

3 years ago

Researchers studying two populations of wolves conducted a two-sample tt-test for the difference in means to investigate whether

Stells [14]

Answer:

A. Assuming that the mean weights of wolves in the populations are equal, the probability of obtaining a test statistic that is greater than 2.771 or less than −2.771 is 0.01.

Step-by-step explanation:

5 0

4 years ago

The first- and second-year enrollment values for a technical school are shown in the table below: Enrollment at a Technical Scho

lyudmila [28]

Answer:

The solution to f(x) = s(x) is x = 2012.

Explanation:

Rewrite the table and the choices for better understanding:

Enrollment at a Technical School

Year (x) First Year f(x) Second Year s(x)

2009 785 756

2010 740 785

2011 690 710

2012 732 732

2013 781 755

Which of the following statements is true based on the data in the table?

The solution to f(x) = s(x) is x = 2012.

The solution to f(x) = s(x) is x = 732.

The solution to f(x) = s(x) is x = 2011.

The solution to f(x) = s(x) is x = 710.

<h2>Solution</h2>

The question requires to find which of the options represents the solution to f(x) = s(x).

That means that you must find the year (value of x) for which the two functions, the enrollment the first year, f(x), and the enrollment the second year s(x), are equal.

The table shows that the values of f(x) and s(x) are equal to 732 (students enrolled) in the year 2012, x = 2012.

Thus, the correct choice is the third one:

The solution to f(x) = s(x) is x = 2012.

5 0

4 years ago