Answer:
1. d/a+c=d
2. (m+21)/5=n
3. (1/2+2q)*4=p or 2+8q=p
4. (p-2a)/2pi=r
5. {[(5c+1)/2]+c}/3=a
6(4x + 5) = 3(x + 8) + 3
24x + 30 = 3x + 24 + 3
24x + 30 = 3x + 27
24x - 3x = 27 - 30
21x = - 3
x = -3/21
x = - 0.143 <==
Step-by-step explanation:
Let's say R is the initial radius of the sphere, and r is the radius at time t.
The volume of the sphere at time t is:
V = 4/3 π r³
Taking derivative with respect to radius:
dV/dr = 4π r²
This is a maximum when r is a maximum, which is when r = R.
(dV/dr)max = 4π R²
This is 4 times the sphere's initial great circle area, but not the great circle circumference. The problem statement contains an error.
Answer:
C. Many ang sagot............
A. Triangle...........................
