This is the most easier question anyone has asked yet. kill me
        
             
        
        
        
-4/9/-1/3=4/3 
HOPE THIS HELPED! IM NOT THAT GREAT AT MATH! SORRY IF IM WRONG!
        
             
        
        
        
Answer:
79.91% of loaves are between 26.94 and 32.18 centimeters
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean  and standard deviation
 and standard deviation  , the zscore of a measure X is given by:
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What percentage of loaves are between 26.94 and 32.18 centimeters
This is the pvalue of Z when X = 32.18 subtracted by the pvalue of Z when X = 26.94.
X = 32.18:



 has a pvalue of 0.8621
 has a pvalue of 0.8621
X = 26.94:



 has a pvalue of 0.0630
 has a pvalue of 0.0630
0.8621 - 0.0630 = 0.7991
79.91% of loaves are between 26.94 and 32.18 centimeters
 
        
             
        
        
        
KE = 0.5*m*v2
KE = (0.5) * (1000 kg) * (20 m/s)2